Answer:42%
Step-by-step explanation:
3x-2y=-5
3y-4x=8
1) multiply the first equation by 3
3(3x-2y=-5) this will give you the new equation: 9x-6y=-15
2) multiply the second equation by 2
2(3y-4x=8) this should give you the equation: 6y-8x=16
3) combine both equations/ like terms
9x-6y=-15
6y-8x=16
4) -6y and 6y cancel out
9x=-15
-8x=16
5) 9x and -8x combine to make 1x or just x and -15 combined with 16 gives you just 1
6) we are now left with:
x=1
7) plug in the x to any of the two original equations ( i chose the first)
3x-2y=-5
3(1) - 2y = -5
3 - 2y = -5
-2y = -8
y = 4
When you plug in the x=1 you are given 3(1) - 2y = -5
Distribute the 3 and you should have 3 - 2y = -5
Subtract 3 from 3 (this cancels out) then from -5
This should leave you with -2y = -8 ( -3 and -5 add to -8)
Divide by -2 ( -2 divided by -2 cancels out)
-8 divided by -2 gives you 4 (two negatives make a positive)
So, y=4 and x=1
To check, plug in x=1 and y=4 into one equation. when you're done with that you can plug them into the other. when you plug them into the first equation you get -5=-5 which means they worked. when plugged into the second, the result is 8=8 which means x=1 and y=4 worked for both equations.
Answer:
Option D
Step-by-step explanation:
Segment BD = Segment BD by reflexive property.
And that will also complete the congruence by AAS postulate.
Answer:
Step-by-step explanation:
Let
x------> the length of the original play space
y-----> the width of the original play space
we know that
The area of the original play space is equal to
The area of the new play space is equal to
Find the difference
