Answer:
120
Step-by-step explanation:
all complementary angles should add up to 180 degrees
Step-by-step explanation:
<h2>
<em><u>You can solve this using the binomial probability formula.</u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.</u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows:</u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: </u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) </u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2</u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157</u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154</u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008</u></em></h2><h2>
<em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)</u></em></h2>
Letter C is correct.
When the function is even, (all powers are even) both ends will go in the same direction.
In this case since the leading coefficient is negative, both ends will go down.
Answer:
Ishaan is 49 years old.
Step-by-step explanation:
Let the present age of Christopher be 'C'.
Let the present age of Ishaan be 'I'.
From the given data, we can form equations which will help us solve the problem.
Christopher is 20 years younger than Ishaan. This means:
C = I - 20 . . . (1)
Fourteen years ago, Ishaan would have been (I -14) years old and Christopher (C - 14) years old.
From the data, I - 14 = 3(C - 14) . . . (2)
Substituting the value of C in Equation 2, we get:
I - 14 = 3(I - 20 - 14)
⇒ I - 14 = 3(I - 34)
⇒ I - 14 = 3I - 112
⇒ 2I = 112 + 14 = 98
⇒ I = 49
So, Ishaan is 49 years old.
Answer:
A. x = -3
B. x = 2
C. x = 9/10
Step-by-step explanation:
(A) –12x + 9 = –15x
Collect like terms
9 = -15x + 12x
9 = -3x
x = 9 / -3
x = -3
(B) 4.5x + 11.5 = 8.5x + 3.5
4.5x - 8.5x = 3.5 - 11.5
-4x = -8
x = -8 / -4
x = 2
(C) 23x – 9 = 13x
-9 = 13x - 23x
-9 = -10x
x = -9 / -10
x = 9/10
