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Ipatiy [6.2K]
3 years ago
11

K is the midpoint of JL J K L If: JK = 5x-2 and KL = 9x - 30 Find JL.

Mathematics
2 answers:
german3 years ago
8 0

Answer:

14x+32

Will be the Answer of this question

Isn't it?

Annette [7]3 years ago
5 0

Answer: 14x-32

Step-by-step explanation:

JL = JK+KL

JL = 5x-2+9x-30

JL = 14x-32

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Plz help I am very confused on this
user100 [1]

Answer:

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Step-by-step explanation:

(-4, 0)

8 0
3 years ago
Identify the equation for the graph shown.
mario62 [17]

Answer:

D

Step-by-step explanation:

The graph shows a y-intercept of 5, and so D is the only answer that could be correct.

8 0
3 years ago
A train leaves Miami at 3:00pm. A second train leaves the same city in the same direction at 5:00pm. The second train travels 50
Alexxandr [17]
Let the speed of the first train be v mph. Then the speed of the second train is:
(v + 50) mph.
Distance traveled by the first train from 3pm to 7pm = 4v miles.
The second train travels 4v miles in 2 hours (from 5pm to 7pm). Therefore the speed of the second train = (4v)/2 = 2v.
However the speed of the second train is also given by (v + 50) mph.
v + 50 = 2v
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The speed of the first train is 50 mph and the speed of the second train is 100 mph.
4 0
3 years ago
Find the distance between the points (6,5√5) and (4,3√2).<br> 2, 2√2, 2√3
FromTheMoon [43]

Answer:

D=\sqrt{(147-30\sqrt{10}}

Step-by-step explanation:

Here we are required to find the distance between two coordinates. We will use the distance formula to find the distance

The distance formula is given as

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here we are given two coordinates as

(6,5\sqrt{5} ) , (4,3\sqrt{2} )

Substituting these values in the Distance formula given above we get

D=\sqrt{(6-4)^2+(5\sqrt{5} -3\sqrt{2}) ^2}

D=\sqrt{(2)^2+(5\sqrt{5})^2+(3\sqrt{2})^2-2*5\sqrt{5}*3\sqrt{2}}\\

D=\sqrt{4+125+18-2*15\sqrt{10}}\\D=\sqrt{147-30\sqrt{10}}\\

Hence this is our answer

6 0
3 years ago
45+72=5(5+9)
Nastasia [14]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
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