Answer:
G(12) = 15
Step-by-step explanation:
When doing g(x) equations, all you do is substitute the value inside the parentheses to x in the equation.
So you get 3/4(12) + 6.
Then simplify to get g(12) = 15
Answer:
option A
Step-by-step explanation:
<h2><em>Note: </em></h2>
when there is an open circle, that means Less than or equal to.
if and when there is a Closed, colored Circle, It's Greater than or equal to or less than or equal to
To solve this problem, we have to manually
solve for the value of x for each choices or equations. The correct equation
will give a value of -1 since the linear equations intersects at point (-1,
-4).
<span>1st: 7x + 3 = x + 3</span>
7x – x = 3 – 3
6x = 0
<span>x = 0 (FALSE)</span>
<span>2nd: 7x − 3 = x – 3</span>
7x – x = 3 – 3
6x = 0
<span>x = 0 (FALSE)</span>
<span>3rd: 7x + 3 = x − 3</span>
7x – x = - 3 – 3
6x = -6
<span>x = -1 (TRUE)</span>
<span>4th: 7x − 3 = x + 3</span>
7x – x = 3 + 3
6x = 6
<span>x = 1 (FALSE)</span>
Therefore the answer is:
<span>7x + 3 = x − 3</span>
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
2.. expecting something else ?
