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3 years ago

Find x Secant tangent angles Helpppp

Mathematics

1 answer:

valentinak56 [21]3 years ago

5 0

Answer:

x = 139

Step by Step Explanation:

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What is the diameter of the following circle (x+4)^2 + (y-9)^2 = 18

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Radius = sqrt(18) = 3*sqrt(2)

diameter = 2(3sqrt(2)) = 6sqrt(2)

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4 years ago

What is the name of a figure made of 6 congruent squares

ozzi

Answer:

B) Cube

Step-by-step explanation:

A) square pyramid has one square base and 4 congruent triangles

B) Cube has 6 congruent squares

C) Rectangular pyramid has one rectangle base and 4 congruent triangles

D) Rectangular prism has 3 sets of rectangles; total of 6 rectangles

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What is the percentage change in total number of players from Tram A 2021 to 2022 when more than 6 but less 20 matches where won

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Step-by-step explanation:

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2 years ago

Find the tangent line approximation for 10+x−−−−−√ near x=0. Do not approximate any of the values in your formula when entering

Svetllana [295]

Answer:

$L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$

Step-by-step explanation:

We are asked to find the tangent line approximation for $f(x)=\sqrt{10+x}$ near $x=0$ .

We will use linear approximation formula for a tangent line $L(x)$ of a function $f(x)$ at $x=a$ to solve our given problem.

$L(x)=f(a)+f'(a)(x-a)$

Let us find value of function at $x=0$ as:

$f(0)=\sqrt{10+x}=\sqrt{10+0}=\sqrt{10}$

Now, we will find derivative of given function as:

$f(x)=\sqrt{10+x}=(10+x)^{\frac{1}{2}}$

$f'(x)=\frac{d}{dx}((10+x)^{\frac{1}{2}})\cdot \frac{d}{dx}(10+x)$

$f'(x)=\frac{1}{2}(10+x)^{-\frac{1}{2}}\cdot 1$

$f'(x)=\frac{1}{2\sqrt{10+x}}$

Let us find derivative at $x=0$

$f'(0)=\frac{1}{2\sqrt{10+0}}=\frac{1}{2\sqrt{10}}$

Upon substituting our given values in linear approximation formula, we will get:

$L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}(x-0)$

$L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}x-0$

$L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$

Therefore, our required tangent line for approximation would be $L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$ .

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