Question

1.

Answer 1

Using implicit differentiation, it is found that the area of the square is increasing at a rate of:

• A. 4.8 m²/min

The area of a square of side length l is given by:

$A = l^2$

Applying implicit differentiation, the rate of change is given by:

$\frac{dA}{dt} = 2l\frac{dl}{dt}$

• The side is 3 m in length, hence $l = 3$.

• Growing at a rate of  0.8 m/min, hence $\frac{dl}{dt} = 0.8$

Then:

$\frac{dA}{dt} = 2l\frac{dl}{dt} = 2(3)(0.8) = 4.8$

Hence, option A is correct.

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