Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
Answer:
8 boys and 10 girls
Step-by-step explanation:
If the ratio is 4:5,
4x2 + 5x2 equal 8+10 =
18.
4:5=8:10
Answer:
15 + x = 38
KEY:
<u>Increased = addition</u>
is= equals to
a number = put any random letter, or my choice is just using "x" so its just means a varaible
HOPE THIS HELPED!!!!! :D
1. Find the Least Common Denominator (LCD) of

Method 1: By Listing Multiples<span>List out all multiples of each denominator, and find the first common one.
5: 5,10
2: 2, 4, 6, 8,10</span>
Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
5 : 5
2 : 2
Therefore, the LCD is 2 x 5 = 10
2. Make the denominators the same as the LCD

3. Simplify. Denominators are now the same

4. Join the denominators

5. <span>Simplify
</span>

<span>Done (Fact: Decimal Form 0.9)</span>