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elixir [45]
3 years ago
15

Pls help me asap on m beestar

Mathematics
2 answers:
vladimir2022 [97]3 years ago
6 0

Answer:

For question 9, the answer is B. This is because for first step, she should have done:

8(n+20) = (8*n) + (8*20)

Step-by-step explanation:

melomori [17]3 years ago
3 0
10. is choice a
hope i helped
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The expression 1.08 + 1.02b predicts the end- of the year value if a financial portfolio where S is the value of the stocks and
iragen [17]

Answer:

We have

Stock = $200

Bonds = $100

Substitute these values into 1.08s+1.02b, where 's' is stock and 'b' is bond

.() + .() =

Predicted end of year value is $318

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3 years ago
The transformation that can result in a figure that is NOT congruent to the original is:
ddd [48]
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4 years ago
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How do i find the volume of these similar solids? round to the nearest tenth HELP
FromTheMoon [43]

Answer:

The volume of the larger solid is 592.6\ mm^3

Step-by-step explanation:

<u><em>The question is</em></u>

If these solids are similar, find the volume of the larger solid

step 1      

Find the scale factor

we know that

If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

x ----> the height of the larger solid in mm

y ----> the height of the smaller solid in mm

z ---> the scale factor

z=\frac{x}{y}

we have

x=4\ mm\\y=3\ mm

substitute

z=\frac{4}{3} ---> scale factor

step 2

Find the volume of the larger solid

we know that

If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

x ----> the volume of the larger solid in cubic millimeters

y ----> the volume of the smaller solid in in cubic millimeters

z ---> the scale factor

z^3=\frac{x}{y}

we have

z=\frac{4}{3}

y=250\ mm^3

substitute the values

(\frac{4}{3})^3=\frac{x}{250}

solve for x

(\frac{64}{27})=\frac{x}{250}

x=250(\frac{64}{27})

x=592.6\ mm^3

4 0
3 years ago
What is the answer plz help
Serhud [2]
The answer is A) candy
7 0
3 years ago
Can someone help me with this page?
Roman55 [17]
Sure
i will help with the page if i can do it…

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3 years ago
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