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AVprozaik [17]
2 years ago
15

Pls help me!!!!!!!!!!!!!

Mathematics
1 answer:
svlad2 [7]2 years ago
4 0

Answer:

Step-by-step explanation:

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The table of values represents a linear function g(x), where x is the number of days that have passed and g(x) is the balance in
goblinko [34]

Answer:

the answer on edge is part c

Step-by-step explanation:

On edge its Part C but i dont know if thats gonna be correct for you or not.

LET ME KNOW if u got it correct

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5 0
2 years ago
Complete the problem to represent the situation given by the equation 0.40e + 10 + 15 = 0.20e + 5 + 25. At one store a trophy co
olganol [36]

Answer: The number of letters that must be engraved for the costs to be the same is 125.

Step-by-step explanation:

Since we have given that

0.4e+10+15=0.20e+5+25

We need to find the number of letters.

0.4e+25=0.2e+30\\\\0.4e-0.2e=30-25\\\\0.2e=25\\\\e=\dfrac{25}{0.2}\\\\e=125

Hence, the number of letters that must be engraved for the costs to be the same is 125.

8 0
3 years ago
Read 2 more answers
Which is NOT a true statement?
Butoxors [25]
A

This is because 4x18 = 72
Hope this helps
6 0
2 years ago
Read 2 more answers
Can someone help me ! thx!!
Bond [772]
It should be 100 because it has to add up to 180 and 50+30=80 so the third angle must be 100
5 0
2 years ago
A random sample of 18 graduates of a certain secretarial school typed an average of 80.6 words per minute with a standard deviat
insens350 [35]

Answer: ( 77.27 , 83.93)

Therefore at 95% confidence/prediction interval is

= ( 77.27 , 83.93)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 80.6 words per minute

Standard deviation r = 7.2

Number of samples n = 18

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

80.6+/-1.96(7.2/√18)

80.6+/-1.96(1.697056274847)

80.6 +/- 3.33

= ( 77.27 , 83.93)

Therefore at 95% confidence/prediction interval is

= ( 77.27 , 83.93)

7 0
3 years ago
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