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stira [4]
3 years ago
15

How does the average distance between galaxies now compare with the average distance between galaxies at the time the supernova

exploded?
Geography
2 answers:
Travka [436]3 years ago
8 0

Answer: dnow/dpast =

2.9

Explanation:

horsena [70]3 years ago
5 0

Stretching of the Universe results in white dwarf supernova, an observed distant had a cosmological red shift of z = 1.6, the cosmological red shift value indicates the Hubble/recession velocity or distance of the object.

Answer:

The formula for these kind of problems is:

Z = ((distance now)/ (distance before)) - 1

We know, Z=1.6

So, we get:

(Distance now)/ (distance before) = 1.6 + 1 = 2.6

Explanation:

The massive cosmic explosions due to burning of stars instead of fading ends their evolution is known as supernovae. The supernovae explosion leads to dropping of matter into space at nearly nine thousand to twenty five thousand miles that is 15,000 to 40,000 km/s. These unconditional blasts produce most of the materials in the universe which includes some elements, such as iron, which helps to make up our needs and even our planets'. The Supernovae is solely responsible for produced heavy elements, so we carry the remains of these distant explosions within our own bodies.

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Much of Japan has a long growing season because of _____.
WINSTONCH [101]

Answer:

C. Because of a warm water ocean flow

Explanation:

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List mechanism of monsoon in India climate​
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Indian Monsoons are Convection cells on a very large scale. They are periodic or secondary winds which seasonal reversal in wind direction. India receives south-west monsoon winds in summer and north-east monsoon winds in winter.

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1 year ago
How did weathering help to shape the Appalachian Mountains?
iragen [17]

Answer:

B

Explanation:

A is incorrect because the Appalachians are not jagged and point

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8 0
2 years ago
Suppose that two stars in a binary star system are separated by a distance of 80 million kilometers and are located at a distanc
jonny [76]

Answer: 1) Angular separation equals 0.0000031 degrees

2) Angular separation in arc -seconds equals 0.011156"

Explanation:

For 2 stars separated by a distance 'S' and at a distance 'D' from the earth the angular separation in radians is given

\theta _{rad}=\frac{S}{D}

Applying values we get

\theta _{rad}=\frac{80\times 10^{6}}{150\times 9.46\times 10^{12}}\\\\\therefore \theta _{rad}=\frac{1}{18487500}radians

Now we know that 'π' radians equals 180 degrees thus the above value in degrees shall be equal to

\therefore \theta _{degrees}=\frac{1}{18487500\times \pi }\times 180^{o}=0.0000031^{o}

2)

The angular separation in arc- seconds is given by

\theta ''=\theta ^{o}\times 3600\\\\\theta'' = 0.0000031\times 3600=0.011156"

8 0
2 years ago
PERSON WILL GET BRAINEST
Mariulka [41]
I am pretty sure it is C but correct me if I'm wrong hope this helps.
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3 years ago
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