Answer:
t ≤ 4x + 10
Step-by-step explanation:
The amount of money that Josh spends on rides is the variable T, found in the problem. Josh wants to spend AT MOST t. That means he can spend as little as he wants, but he can't ride too many times so that the cost goes over T. Therefore, it has to be less than. But, it can also be equal to, as he can ride exactly many rides up to T, it just can't go over it.
Next, the cost to get into the fair is ten dollars, meaning if he goes on only one ride, that will cost him 4 dollars, but actually will have cost him 14 dollars because of the entrance fee. So, no matter how many rides he goes on, there is always the entrance fee added on.
Finally, the cost for each ride is 4 dollars per ride or 4 times x with x being the number of rides he goes on.
So, for our answer, we have t ≤ 4x + 10!
Answer:
well I don't have a picture to explain it but (0,8) would be on the y axis and 8 on the x-axis ( it would go up 8 times and stay on the same line)
it would be -3 on the y axis and it wouldn't move up or down (move 3 points to the left)
Step-by-step explanation:
(x,y) when the x is 0 it doesn't move on the x-axis (left or right) and when it is 0 it doesn't move on the y-axis (up or down)
hope that makes sense!
Ok, so one way is like your way
so
if we test some numbers
for x=10
we get about 12.3/10≈1.2
for x=100000
we get 1522.03/100000≈0.01522
the top number keeps getting smaller reletive to bottom number
when x=1000000000
we get 8899.68/1000000000≈0.000009
we notice the bottom number is increaseing at a faster rate that the botom one
when x approaches infinity,the bottom number will be so big it will become a fraction that evaluates to basically zero becuase it evaluates to a very small number that is negligible
