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mylen [45]
3 years ago
9

Please help! circled numbers only. tysm, ILL MARK BRAINLIEST!

Mathematics
2 answers:
NeX [460]3 years ago
8 0
2. 4 2/5
4. 6 3/8
6. 4 5/12
8. 2 1/3
10. 24 2/3
12. 7 5/6
14. 33/5
16. 102/11
18. 81/5
20. 163/7
22. 1295/6
24. 1329/16
guajiro [1.7K]3 years ago
3 0

Answer:

2) 4 and 2/5

4) 6 and 3/8

6) 4 and 5/12

8) 2 and 1/3

10) 24 and 2/3

12) 7 and 5/6

14) 33/5

16) 102/11

18) 81/5

20) 163/7

22) 1295/6

24) 1329/16

Step-by-step explanation:

Hope this helps! Pls give brainliest!

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Amanda and Franco left a library at the same time and cycled in opposite directions back toward their homes.
monitta

Answer:

200 Meters per minute

Step-by-step explanation:

Amanda went 180mpm constantly for 15 minutes. 180 times 15= 2700.

5700-2700=3000

3000 meters divided by 15 minutes= 200 meters per minute

8 0
3 years ago
a jar contains 16 marbles of which 1 is blue 5 are red and the rest are green what is the ratio of green marbles to all marbles
charle [14.2K]

Answer:

5:3

Step-by-step explanation:

16-(5+1)=10

Ratio is 10:6 reduced is 5:3

4 0
3 years ago
Maria earns $12/hour as a store clerk. This week she worked 49 hours. Estimate her
Ghella [55]

Answer:

a= $1,068 without overtime pay

b= $1,122 with overtime pay

Step-by-step explanation:

a = (12 \times 49) + (12 \times 40) \\  = 1068

b = (9(12 \times 1.5) + (12 \times 40)) + (12 \times 40)\\ = 1122

7 0
2 years ago
Solve the equation and check your solution. (If an answer does not exist, enter DNE. If all real numbers are solutions, enter RE
r-ruslan [8.4K]
5x-4=4x+8
-4x. -4x
X-4=8
+4. +4
X=12
5(12)-4=4(12)+8
60-4=48+8
56=56
5 0
3 years ago
How do I use the following cosine equation to get the Sinusoid Max & Min Times (x values), and Sinusoid Max and Min Values (
Paraphin [41]

9514 1404 393

Answer:

  • maximum: (x, y) = (12.4n+3.2, 186.322)
  • minimum: (x, y) = (12.4n+9.4, 163.498)

Step-by-step explanation:

You know that cos(α) is a maximum at α=0, 2π, 4π, and all even multiples of π. You know cos(α) is a minimum for α=π, 3π, 5π, and all odd multiples of π.

You can find your value of x at which y will be a maximum by setting the argument of the cosine function equal to zero (and/or 2nπ). If we use α=2nπ, then we have ...

  α = (5π/31)(x -3.2) = 2nπ

  (x -3.2) = (31/5)(2n) = 12.4n

Tidal maxima will occur at ...

 x = 12.4n +3.2 . . . . . for integer values of n

Without bothering to go through the solution for α being odd multiples of π, we can see from this that the period is 12.4 hours. We know the tidal minimum  will be half a period later, or 6.2 hours later than this.

Tidal minima will occur at ...

  x = 12.4n +9.4 . . . . for integers n

__

Of course, cos(α) has extremes of ±1, so your tidal maximum will be ...

  y = 11.412 +174.91 = 186.322

and your tidal minimum will be ...

  y = -11.412 +174.91 = 163.498

4 0
3 years ago
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