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2 years ago

15

Jackie so $9500 worth of vacuum cleaners in December if she earns a commission rate of 15% of all sales what commission Did sh

e earn

1 answer:

artcher [175]2 years ago

8 0

Answer:

1425

Step-by-step explanation:

I'm pretty sure 1425 is 15% of 9500.

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The area of a square is 676 square yards how long is each side of the square

kogti [31]

So basically what you want to do is square root this, since to find the area of a square from the side length, you square it, (x * x, because the area for a quadrilateral is base * height, and a square has the same length of sides).

So there is no way to properly square root a number unless you memorize it. However, what you can do, is look at the last digit and make an approximation, at which two numbers multiply together to have a last digit of 6.

So, 4 * 4 and 6 * 6 are the two that square to have a last digit of 6.

(1: 1, 2: 4, 3: 9, 4: 6, 5: 5, 6: 6, 7: 9, 8: 4, 9: 1, 0: 0) If that makes any sense.

So basically the square root has to end with 4 or 6.

Now, you can just approximate. It would be over 20, because 20 squared (20 * 20) is equal to 400. But it would be under 30, because 30 squared is 900.

So the two possible numbers are 24 and 26.

If you square both of them, you find that:

24 squared = 576

26 squared = 676

So therefore 26 is the square root of 676, so therefore one side is 26 yards.

Hope this weirdly long explanation helped :)

4 0

3 years ago

Read 2 more answers

Find the parity of the following if a and b have different parities.<br> (5a - 3b)(a² + 5b) + 2

sp2606 [1]

9514 1404 393

Answer:

odd

Step-by-step explanation:

If 'a' and 'b' have different parity, the result has odd parity.

__

<u>Assume a=odd, b=even</u>

(5·odd -3·even) = odd

(odd^2 +5·even) = odd

(odd)(odd) +2 = odd

__

<u>Assume a=even, b=odd</u>

(5·even -3·odd) = odd

(even^2 +5(odd)) - odd

(odd)(odd) +2 = odd

_____

The attached verifies this with numbers.

4 0

2 years ago

Evaluate 3p^2 + 7 (3 times p to the second power plus 7), when p = 4

frosja888 [35]

Answer:

55

Step-by-step explanation:

3p²+7

= 3 ×4²+7

= 3× 16+7

= 48 +7

=55

3 0

2 years ago

A study of the pricing accuracy of checkout scanners at a store found that one of every 20 items is priced incorrectly. On any g

GalinKa [24]

Answer:

a) There are going to be at least 15 items both priced correctly, and incorrectly, which means that we can use the normal approximation to the binomial to solve the exercise in this supposed problem.

b) 20.36% probability that exactly one of the five items is priced incorrectly by the scanner

c) 22.62% probability that at least one of the five items is priced incorrectly by the scanner

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is priced correctly, or it is not. The probability of an item being priced incorrectly is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Five items selected.

This means that $n = 5$

One of 20 is priced incorrectly.

This means that $p = \frac{1}{20} = 0.05$

a) Assuming that this store sells thousands of items every day, which probability distribution would you use and why?

There are going to be at least 15 items both priced correctly, and incorrectly, which means that we can use the normal approximation to the binomial to solve the exercise in this supposed problem.

b) What is the probability that exactly one of the five items is priced incorrectly by the scanner?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.05)^{1}.(0.95)^{4} = 0.2036$

20.36% probability that exactly one of the five items is priced incorrectly by the scanner

c) What is the probability that at least one of the five items is priced incorrectly by the scanner?

Either no items are priced incorrectly, or at least one is. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 0$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.05)^{0}.(0.95)^{5} = 0.7738$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7738 = 0.2262$

22.62% probability that at least one of the five items is priced incorrectly by the scanner

5 0

3 years ago

ASAP I WILL GIVE BRAINEST <br><br> GEOMETRY

Wewaii [24]

Pretty sure the answer is SAS because SSS only work on right triangles and this triangle has an angle

4 0

2 years ago