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Olenka [21]
3 years ago
13

One of the factors of g2 – 28g + 196 is:

Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0
G^2 - 28g + 196 = g^2 - 14g - 14g + 196 = (g^2 - 14g) + (-14g + 196) = g(g - 14) - 14(g - 14) = (g - 14)(g - 14)
Therefore, one of the factors of g^2 - 28g + 196 is g - 14
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Answer To Question (A) 
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Answer To Question (B)
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4 years ago
A bike rental company charges a $5 service fee and $1 per hour. If this situation is represented as a function, what would be th
Elenna [48]
Write as a function equation: where f(x) is the same as "y"

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4 0
3 years ago
Read 2 more answers
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balu736 [363]

1. 3*3 + 3*8 = 9+24=33

2. 4*4+.5*2*4+5*5= 16+4+25=45

3. 5*10+4*10= 90

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3 0
3 years ago
Paul has 2/3 as many postcards as Shawn. The number of postcards Shawn has is 4/5 of the number of postcards Tim has. If the thr
ahrayia [7]

Tim has 56 more postcards than Paul.

Step-by-step explanation:

Total postcards boys have = 280

Let,

x = Paul's postcards

y = Shawn's postcards

z = Tim's postcards

According to given statement;

x + y + z = 280      Eqn 1

x=\frac{2}{3}y                   Eqn 2

y = \frac{4}{5}z                   Eqn 3

Putting value of y from Eqn 3 in Eqn 2

x=\frac{2}{3}*\frac{4}{5}z\\\\x=\frac{8}{15}z            Eqn 4

Putting value of x and y from Eqn 4 and Eqn 3 in Eqn 1

\frac{8}{15}z+\frac{4}{5}z+z=280\\\\\frac{8z+12z+15z}{15}=280\\\\\frac{35z}{15}=280\\\\

Multiplying both sides by \frac{15}{35}

\frac{15}{35}*\frac{35}{15}z=280*\frac{15}{35}\\z=120

Putting z=120 in Eqn 3

y=\frac{4}{5}*120\\y=96

Putting y=96 in Eqn 2

x=\frac{2}{3}*96\\x=64

Difference of Tim and Paul = 120-64 = 56

Tim has 56 more postcards than Paul.

Keywords: linear equation, substitution method

Learn more about substitution method at:

  • brainly.com/question/10557938
  • brainly.com/question/10600222

#LearnwithBrainly

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3 years ago
If both pairs of opposite sides of the quadrilateral are congruent, then the quadrilateral is a?
Bond [772]

Answer:

B (parallelogram)

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