Answer is
<span>Multiplication Property of Equality
</span>
hope it helps
Answers with explanations:
Problem 2-
First we have to insert our numbers into the equation. So we would have
l2l-l-7l
The ll bars mean to find the absolute value. Absolute value is how many spaces it is between that number and zero. So we can simply this to
2-7=-5
Problem 3-
First, we have to insert our numbers into the problem.
2(-2)^3(3)
Using PEMDAS or order of operations, we solve the exponent first and simplify from there
2(-8)(3)
(-16)(3)
(-48)
The answer is -48
Problem 4-
Again, we have to input the numbers into the equation.
(4^2-4(-3))/2
(16-4(-3))/2
(16+12)/2
(28)/2
14
The answer is 14
Problem 5-
(3)(-1)-(-1^2)
(3)(-1)-(1)
-3-1
-4
The answer is -4
Problem 7-
l-3-4l- -3^2
l-3-4l- +9
l-7| - +9
7-+9
-2
The answer is -2
Problem 8-
3(-3)^2-4|-3|+6
3(9)-4|-3|+6
27-4|-3|+6
27-12+6
21
Answer:
x = - 191/28
Step-by-step explanation:
14 (8x + 56) = 20
112x + 784 = 20
112x = 20 - 784
112x = - 764
x = - 764/112
x = - 191/28
Answer: true
Step-by-step explanation:
The polar cordinates are (6, pi/2)
We know that a imaginary number can be written, in polar cordinates (R, θ)
Z = R*(cos(θ) + i*sin(θ))
Then, the point (6, pi/2) is:
Z = 6*(cos(pi/2) + i*sin(pi/2)) = 6i
The other representation is (a, b) and in this case the imaginary number is
Z = a + b*i
In this case we have (0, 6) so:
Z = 0 + 6*i
Then you can see that the statement is true,
Answer:
False
Step-by-step explanation:
Plot the point on desmos graphing calculator
