All categories

3 years ago

HELP ME PLEASEEEEEEEEEEEEEEEE

Mathematics

2 answers:

hoa [83]3 years ago

5 0

90 mm ..................

Ira Lisetskai [31]3 years ago

4 0

Answer:

90 mm^2

Step-by-step explanation:

Divide it in 2 figures

Get the area of the one of 5 * 6 mm = 30mm^2

Then the one of 6 * 10 mm = 60 mm^2

Then just add it up. 90 mm^2

You might be interested in

An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect

Serggg [28]

Answer:

$k = 1$

$P(x > 3y) = \frac{2}{3}$

Step-by-step explanation:

Given

$f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x } & { \text 0, { elsewhere. } } \end{array} \right.$

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1$

Where

${ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x }$

Substitute values for the interval of x and y respectively

So, we have:

$\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1$

Isolate k

$k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1$

Integrate y, leave x:

$k \int\limits^2_{0} y {dx} \, [0,x/2]= 1$

Substitute 0 and x/2 for y

$k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1$

$k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1$

Integrate x

$k * \frac{x^2}{2*2} [0,2]= 1$

$k * \frac{x^2}{4} [0,2]= 1$

Substitute 0 and 2 for x

$k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1$

$k *[ \frac{4}{4} - \frac{0}{4} ]= 1$

$k *[ 1-0 ]= 1$

$k *[ 1]= 1$

$k = 1$

Solving (b): $P(x > 3y)$

We have:

$f(x,y) = k$

Where $k = 1$

$f(x,y) = 1$

To find $P(x > 3y)$ , we use:

$\int\limits^a_b \int\limits^a_b {f(x,y)}$

So, we have:

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 dxdy$

Integrate x leave y

$P(x > 3y) = \int\limits^2_0 x [0,y/3]dy$

Substitute 0 and y/3 for x

$P(x > 3y) = \int\limits^2_0 [y/3 - 0]dy$

$P(x > 3y) = \int\limits^2_0 y/3\ dy$

Integrate

$P(x > 3y) = \frac{y^2}{2*3} [0,2]$

$P(x > 3y) = \frac{y^2}{6} [0,2]\\$

Substitute 0 and 2 for y

$P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}$

$P(x > 3y) = \frac{4}{6} -\frac{0}{6}$

$P(x > 3y) = \frac{4}{6}$

$P(x > 3y) = \frac{2}{3}$

8 0

3 years ago

True or False percent markup on selling price can be converted to percent markip on cost by formula?

IRINA_888 [86]

The correct answer is True.

3 0

3 years ago

A watermelon seed is 0.4cm long. How far would a line of 124 watermelon seeds stretch? Write your answer in meters.

Ahat [919]

Distance stretched = 0.4 * 124 = 49.6 cms

converting to meters we divide by 100:-

Answer is 0.496 meters

6 0

3 years ago

BRAINLIEST. NEED HELP NOW!!!<br> What is the value of x?

Arturiano [62]

Answer:

x=10

Step-by-step explanation:

these are similar triangles

8 12

------ = -----------

x+4 2x+1

using cross products

8* (2x+1) = 12(x+4)

distribute

16x + 8 = 12x+48

subtract 12x from each side

16x-12x +8 = 12x-12x+48

4x+8 = 48

subtract 8 from each side

4x+8-8 = 48-8

4x = 40

divide by 4

4x/4 = 40/x

x =10

3 0

3 years ago

What is the slope of the line y=1/8x-1

Eva8 [605]

Answer:

1/8x ... -1 would be the y intercept so 1/8x is the slope

5 0

3 years ago