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Nataly_w [17]
3 years ago
10

Help please! im not sure which graph is which

Mathematics
1 answer:
Wewaii [24]3 years ago
8 0

WHat do you mean when you say you don't know "which graph is which"

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How would I solve this. <br> If you answer I will give brainliest.
kobusy [5.1K]

Answer:

∠ QPR = 64.5°

Step-by-step explanation:

The chord- chord angle QPR is half the sum of the arcs intercepted by the angle and its vertical angle, then

∠ QPR = \frac{1}{2} (QR + ST ) = \frac{1}{2} (98 + 31)° = 0.5 × 129° = 64.5°

5 0
3 years ago
An antique clock cost $540. Its price is increased by 18% in a year. What is it now worth?
lisabon 2012 [21]
Explanation:

Cost=$540
Increased amount= $(18/100*540) = $97.2
Cost now= $(540+97.2) = $637.2
Answer: The antique clock worths $637.2 now.

Hope it helps u! :)
4 0
3 years ago
∠BAD is bisected by . If m∠BAC= 2x - 5 and m∠CAD = 145, the value of x is 150 145 75 70
horsena [70]
We are asked to find the value of x given that ∠BAD is bisected by AC and measurement of BAC is equal to 2x - 5 and measurement of CAD is equal to 145. Since they are bisected, they are equal and the solution is shown below:
m ∠ BAC = m ∠ CAD
2x - 5 = 145 , transpose -5 to the opposite side such as:
2x = 145 + 5 , perform addition of 145 and 5
2x = 150
2x / 2 = 150 / 2 , divide both sides by 2
x = 75

The answer is 75 for the x value.


7 0
3 years ago
Read 2 more answers
The cost of a movie ticket in a large city has increased exponentially over the decades since 1953 when records were first kept.
Setler79 [48]

Answer:

(a) C=1.25\cdot (1.5)^{y/10}

(b) $7.44

(c) Yes.

Step-by-step explanation:

The exponential function representing the cost of a movie ticket in a large city is as follows:

C=1.25\cdot (1.5)^{d}

(a)

A decade equals 10 years.

Then for <em>n</em> decades the number of years will be,

<em>y</em> = 10 × <em>n</em>

Then the equation of the cost of a movie ticket in terms of <em>y</em> years after 1953 is as follows:

C=1.25\cdot (1.5)^{d}

   =1.25\cdot (1.5)^{(10\times n)/10}\\=1.25\cdot (1.5)^{y/10}

The equation represents the cost of a movie ticket in

(b)

For the year 1953, the value of <em>y </em>is 0.

So, for 1996 the value of <em>y</em> will be, 44.

Compute the cost of a movie ticket in 1996 as follows:

C=1.25\cdot (1.5)^{y/10}

   =1.25\cdot (1.5)^{44/10}\\=1.25\times 5.9539\\=7.442375\\\approx 7.44

Thus, the cost of a movie ticket in 1996 will be $7.44.

(c)

It is already provided that the cost of a movie ticket in a large city has increased exponentially over the decades since 1953.

So, for the year 1953 the cost of a movie ticket was, $1.25.

And the cost of a movie ticket in 1996 was $7.44.

This value shows an exponential increase in the cost.

Thus, the estimate in part b is reasonable.

4 0
3 years ago
Solve. 3(a – 5) – 6 = –15
Andre45 [30]

Answer:

a=6

Step-by-step explanation:

distribute:

3a-15-6=-15

combine like terms:

3a-21=-15

add 21 to each side:

3a=6

divide by 3:

a=2

5 0
2 years ago
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