Answer:
Option A: -12x-8=10 is the correct answer.
Step-by-step explanation:
Given equation is:
-4 (3x+2) = 10
We will distribute the equation by multiplying the terms inside the brackets with -4.
Therefore,
-4*3x + 2*-4 = 10
-12x +(-8) = 10
-12x - 8 = 10
The equation -4 (3x+2) = 10 will become -12x-8=10 after distributing.
Hence,
Option A: -12x-8=10 is the correct answer.
Answer:
Step-by-step explanation:
there are infinite numbers between 2 and 3 having average=2.5
2.49,2.51
2.48,2.52
2.47,2.53
2.46,2.54
.................
2.491,2.509
2.492,2.508
2.493,2.507
......................
I think the answer would be 89
Answer:
56
Step-by-step explanation:
The range of a data set is the difference between the largest and the smallest values in that data set. In this case, the largest value in the data set is 119, and the smallest is 63. 119-63=56, which is the range. Hope this helps!
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
