Answer:
The probability is 
.
Step-by-step explanation:
There are 7 democrats and 6 republicans
Number of ways in which 4 democrats and 2 republicans can be selected=![\[{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}\]](https://tex.z-dn.net/?f=%5C%5B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B4%7D%7D%5Ctimes%20%7B%7D%5E%7B6%7D%7B%7BC%7D_%7B2%7D%7D%5C%5D)
Number of ways in which 5 democrats and 1 republican can be selected= ![\[{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}\]](https://tex.z-dn.net/?f=%5C%5B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B5%7D%7D%5Ctimes%20%7B%7D%5E%7B6%7D%7B%7BC%7D_%7B1%7D%7D%5C%5D)
Number of ways in which 6 democrats can be selected = ![\[{}^{7}{{C}_{6}}\]](https://tex.z-dn.net/?f=%5C%5B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B6%7D%7D%5C%5D)
So, favourable outcomes are ![\[{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}+{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}+{}^{7}{{C}_{6}}\]](https://tex.z-dn.net/?f=%5C%5B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B4%7D%7D%5Ctimes%20%7B%7D%5E%7B6%7D%7B%7BC%7D_%7B2%7D%7D%2B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B5%7D%7D%5Ctimes%20%7B%7D%5E%7B6%7D%7B%7BC%7D_%7B1%7D%7D%2B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B6%7D%7D%5C%5D)
Total possible outcomes =![\[{}^{13}{{C}_{6}}\]](https://tex.z-dn.net/?f=%5C%5B%7B%7D%5E%7B13%7D%7B%7BC%7D_%7B6%7D%7D%5C%5D)
Now, probability=![\[\frac{Favourable}{Possible}=\frac{{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}+{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}+{}^{7}{{C}_{6}}}{{}^{13}{{C}_{6}}}=0.383\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7BFavourable%7D%7BPossible%7D%3D%5Cfrac%7B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B4%7D%7D%5Ctimes%20%7B%7D%5E%7B6%7D%7B%7BC%7D_%7B2%7D%7D%2B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B5%7D%7D%5Ctimes%20%7B%7D%5E%7B6%7D%7B%7BC%7D_%7B1%7D%7D%2B%7B%7D%5E%7B7%7D%7B%7BC%7D_%7B6%7D%7D%7D%7B%7B%7D%5E%7B13%7D%7B%7BC%7D_%7B6%7D%7D%7D%3D0.383%5C%5D)
Learn more about probability:
brainly.com/question/2561151?referrer=searchResults
Answer:
I think the answer would be the very first one.
they all need to have '' ( ) '' in them.
if a number is outside of that, it needs to at least have a letter beside the number
here's an example
Factored form:
2x(x + y)
not factored:
2(x - y)
but for the first one, it's correct from the rest of them.
Answer:
C
Step-by-step explanation:
In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:
N1⋅N2=a⋅c=1⋅−12=−12
AND
N1+N2=b=−1
After trying out a few numbers we get N1=3 and N2=−4
3⋅−4=−12, and 3+(−4)=−1
x2−x−12=x2−4x+3x−12
x(x−4)+3(x−4)=0
(x+3)(x−4)=0
Now we equate the factors to zero.
x+3=0,x=−3
x−4=0,x=4
