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amid [387]
3 years ago
8

Determine if the two triangles are congruent.

Mathematics
2 answers:
jeka943 years ago
4 0

Answer: ASA

Step-by-step explanation:  

1: Congruent with an angle of the other triangle. (Check the number of angle markings.) [A]

2: Congruent with a side of the other triangle. [S]

3: Congruent with an angle of the other triangle. (Check the number of angle markings.) [A]

You can match what you have with your answer choices.

A: Angle

S: Side

vova2212 [387]3 years ago
3 0

Answer:

they are not congruent

Step-by-step explanation:

look at all the sides to see if they are all the same

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If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
What is an equation in slope-intercept form of the line that passes through (6, −7)
Ber [7]

Answer:

y = -7/6x

Step-by-step explanation:

y - y1 = m*(x-x1)

m=y/x

y - (-7) = -7/6*(x-6)

y + 7 = -7/6x + 7

y = -7/6x + 7 - 7

y = -7/6

4 0
3 years ago
HELP!!!!!!!!!<br> Please!
beks73 [17]

Answer:

I believe the answer would be 21xy + 6x^2

3 0
3 years ago
A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s
Setler [38]

Answer:

310\text{ feet and }210\text{ feet}

Step-by-step explanation:

GIVEN: A farmer has 520 \text{ feet} of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is 310 \text{ feet}.

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be x and y

perimeter of rectangular pen =2(x+y)=520\text{ feet}

                                                x+y=260

                                               y=260-x

area of rectangular pen =\text{length}\times\text{width}

                                       =xy

putting value of y

=x(260-x)

=260x-x^2

to maximize \frac{d \text{(area)}}{dx}=0

260-2x=0

x=130\text{ feet}

y=390\text{ feet}

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen =310\text{ feet}

                              width of rectangular pen =210\text{ feet}

Maximum area of rectangular pen =310\times210=65100\text{ feet}^2

Hence maximum area of rectangular pen is 65100\text{ feet}^2 and dimensions are 310\text{ feet and }210\text{ feet}

5 0
3 years ago
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