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bija089 [108]
3 years ago
15

Factor 4(3x + 1)2 - 5(3x + 1) + 1 completely.

Mathematics
1 answer:
lord [1]3 years ago
5 0
C is the correct answer
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Scott is selling baseball hats at the store he works at and makes 8% commission on anything he sells. His total sales for one da
jarptica [38.1K]

Answer:

E baboom

Step-by-step explanation:

4 0
3 years ago
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A manufacturer of televisions subjects the equipment to a comprehensive testing process for all essential functions before the t
Vikki [24]

Answer:

The value is   P(X \ge 9) = 0.9138

Step-by-step explanation:

From the question we are told that

  The probability of passing the test is  p =  0.95

  The sample size is  n  =  10  

Generally the distribution of the comprehensive testing of equipment  follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators

  Generally the probability that at least 9 pass the test  is mathematically represented as

    P(X \ge 9) =  P(X = 9 ) + P(X = 10 )

=> P(X \ge 9) =  [^{10}C_9 *  (0.95)^9 *  (1- 0.95)^{10-9}] + [^{10}C_{10} *  (0.95)^{10} *  (1- 0.95)^{10-10}]

=> P(X \ge 9) =  [0.3151] + [0.5987]

=> P(X \ge 9) = 0.9138

7 0
3 years ago
What is the midpoint of FB?
yanalaym [24]

Answer:

2

Step-by-step explanation:

do 9 plus negative 5 then divide by 2 to get your answer

4 0
3 years ago
Read 2 more answers
(5a +7b)b/(b+2b)=? <br> 4a ,4ab , 2a+4b , 5a+7b/3 , 5a+5b
musickatia [10]
The correct answer is:  [D]:  " \frac{5a + 7b}{3} " .
__________________________________________________
Explanation:
__________________________________________________
\frac{b(5a + 7b)}{b +2b} ; 

Simplify the "denominator" ;   →  (b + 2b = 1b + 2b = 3b) ; 

 and rewrite: 

\frac{b(5a + 7b)}{3b} ; 

Cancel out the "b" in the "numerator" to a "1" ; 
              and cancel the "3b" in the "denominator to a "3" ; 

{since:  "b ÷ b = 1 ";  and since:  "3b ÷ b = 3" } ;

and rewrite as:
____________________________________________________
            \frac{5a + 7b}{3} ; 
____________________________________________________

   →  which is:  Answer choice:  [D]:  "  \frac{5a + 7b}{3} " .
____________________________________________________
6 0
3 years ago
Read 2 more answers
What are the solutions of 3t + 2 &lt; 7 or -4t + 5 &lt; 1? Graph the solutions and put each solution in interval notation.
Ghella [55]

Answer:

\displaystyle (-∞, 2\frac{1}{3}) ∪ (1, ∞) \\ \\ 2\frac{1}{3} > t \:OR\: 1 < t

Step-by-step explanation:

3t + 2 < 7 OR −4t + 5 < 1

- 2 - 2 - 5 - 5

___________________

\displaystyle \frac{3t}{3} < \frac{7}{3} \:OR\: \frac{-4t}{-4} < \frac{-4}{-4} \\ \\ t < 2\frac{1}{3} \:OR\: t >1

**Whenever you divide\multiply by a <em>negative</em><em> </em><em>integer</em>, you reverse the inequality symbol given to you <em>initially</em>.

<u>Extended</u><u> </u><u>Information</u><u> </u><u>on</u><u> </u><u>Inequalities</u>

≤, ≥ [dark circle with a dark line (<em>brackets</em><em> </em>when writing in <em>Interval</em><em> </em><em>Notation</em>)]

<, > [<em>light</em><em> </em><em>circle</em><em> </em>with a <em>dashed</em><em> </em><em>line</em><em> </em>(<em>parenthese</em><em>s</em><em> </em>when writing in <em>Interval</em><em> </em><em>Notation</em>)]

I am delighted to assist you at any time.

<em>As</em><em> </em><em>you</em><em> </em><em>can see</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>above</em><em> </em><em>graph</em><em>,</em><em> </em><em>the</em><em> </em><em>graph</em><em> </em><em>is</em><em> </em><em>connected</em><em> </em><em>ALTOGETHER</em><em>.</em><em> </em><em>Be</em><em> </em><em>aware</em><em> </em><em>that</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>not</em><em> </em><em>ALWAYS</em><em> </em><em>be</em><em> </em><em>the</em><em> </em><em>case</em><em> </em><em>because</em><em> </em><em>a</em><em> </em><em>majourity</em><em> </em><em>of</em><em> </em><em>these</em><em> </em><em>graphs</em><em> </em><em>are</em><em> </em><em>seperated</em><em>,</em><em> </em><em>pointing</em><em> </em><em>in</em><em> </em><em>OPPOSITE</em><em> </em>directions.

5 0
2 years ago
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