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Ronch [10]
3 years ago
11

A researcher is testing a hypothesis of a single mean. The critical z value for a = .05 and a two‑tailed test is +1.96. The obse

rved z value from sample data is ‑2.05. The decision made by the researcher based on this information is to _____ the null hypothesis.
Mathematics
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

The decision made by the researcher based on this information is to reject the null hypothesis.

Step-by-step explanation:

Two-tailed hypothesis test:

Critical value: z_c

Test statistic: z

If |z| < |z_c|, we do not reject the null hypothesis.

If |z| > |z_c|, we reject the null hypothesis.

In this question:

z_c = 1.96, z = -2.05, |z| = 2.05

Since |z| > |z_c|, we reject the null hypothesis.

The decision made by the researcher based on this information is to reject the null hypothesis.

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Answer:

-13            

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Step-by-step explanation:

Step  1  :

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Simplify   —

           9

Equation at the end of step  1  :

 4    7

 — -  —

 7    9

Step  2  :

           4

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Equation at the end of step  2  :

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 — -  —

 7    9

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       7  

     The right denominator is :       9  

       Number of times each prime factor

       appears in the factorization of:

Prime  

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Denominator   Right  

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{Left,Right}  

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   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

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  Right_M = L.C.M / R_Deno = 7

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      4 • 9

  ——————————————————  =   —————

        L.C.M              63  

  R. Mult. • R. Num.      7 • 7

  ——————————————————  =   —————

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Final result :

 -13            

 ——— = -0.20635  

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