1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MakcuM [25]
3 years ago
6

What is the range of function g? g (x) = x²+6x-5

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

y | y ≥ 14

have an amazing day <3

You might be interested in
Solve for the variable 7/28 = 25/?
ICE Princess25 [194]
Let x be the unknown number. The equation is going to be 7/28=25/x, now we cross multiply. 7*x=25*28, 7x=700, divide both sides by 7 and you should get 100, So, x=100 and 7/28=25/100
7 0
3 years ago
I’m confused on this one
Lisa [10]

The angle x is half the sum of the intercepted arcs, PQ and NO.

... (1/2)(65° + 45°) = 55° = x° = m∠PMQ

3 0
3 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
Find the domain of f(x) = Square 3 x + 8 ​
vagabundo [1.1K]

The question is a bit ambiguous: you may mean

\sqrt{3x+8}

or

\sqrt{3x}+8

Anyway, in both cases, the domain of a function involving a square root is found by imposing the content of the root to be greateer than or equal to zero. So, in the first case you have

3x+8\geq 0 \iff 3x\geq -8 \iff x\geq -\dfrac{8}{3}

In the second case, you have

3x\geq 0 \iff x\geq 0

6 0
3 years ago
Identify the initial amount a and the rate of growth r (as a percent) of the exponential function y = 12(1.05)t. Evaluate the fu
aleksandrvk [35]

Answer

Exponential function is in the form of : y =a(1+r)^x .....[1]

where a is the initial amount and r is the growth rate and (1+r) is the growth factor.

Given the function: y = 12(1.05)^t

On comparing with equation [1] we have;

Initial amount(a) = 12

1+r = 1.05

Subtract 1 from both sides we get;

r = 0.05 or 5%

Growth (r) = 0.05 or 5%

Now, evaluate the function for t = 5 we have;

Substitute the value of t=5 in the given function we have;

y = 12(1.05)^{5}

y = 12 \cdot 1.27628156 = 15.3153787

Therefore, the value of function when t=5 to the nearest tenth is 15.3

7 0
3 years ago
Other questions:
  • Como Resolver este
    14·1 answer
  • Distance around a shape
    13·1 answer
  • Find slope of a parallel line -16+5x=4y
    10·1 answer
  • HELP ME OUT HERE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    12·1 answer
  • I need help with this, I´ĹL GIVE THE FIRST ANSWER BRAINLIEST
    6·2 answers
  • Henrietta surveyed her high school classmates on their favorite subjects. She recorded their gender and favorite subject. She co
    14·2 answers
  • How do you write the circumference of the circle in terms on 几
    5·1 answer
  • A company made 675 in ticket sales. They sold 100 tickets. How much did the company make per ticket, if each ticket cost the sam
    10·1 answer
  • Which of the angles are corresponding angles?
    15·1 answer
  • Find the sum of the arithmetic sequence 1, 3, 5, 7, … , 99.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!