What is the range of function g?<br> g (x) = x²+6x-5

A study was conducted to determine if the salaries of elementary school teachers from two neighboring districts were equal. A sa

Semenov [28]

Answer:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

(–2975, 175)

Do not reject H₀

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the salaries of elementary school teachers are equal in two districts. You can test this trough the population means of the salaries of the teachers if they are either equal or different or directly test if the difference between the salaries of the two districts is cero or not, symbolically: μ₁ - μ₂ = 0

Remember, in the null hypothesis is usually stated the known information, is the "no change" premise and always carries the = symbol.

The hypothesis is:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

You have two normally distributed variables and you are studying the difference of the means. You can use a pooled Z to make the interval, the formula is:

X[bar]₁-X[bar]₂ ± $Z_{1-\alpha /2}$ *(√(σ₁²/n₁+σ₂²/n₂)

Since the test is two-tailed and at a signification level of 5% I've made the interval at the complementary confidence level of 95% so that I can use it to decide over the hypothesis.

X[bar]₁-X[bar]₂ ± $Z_{1-\alpha /2}$ *(√(σ₁²/n₁+σ₂²/n₂)

$Z_{1-\alpha /2}$ = $Z_{0,975}$ = 1,96

[28900-30300 ± 1.96*(√((2300)²/15+(2100)²/15)]

[-1400 ± 1576,15]

[-2976.15;176,15]

Since I've approximated to two decimal units in the intermediate calculations, the values differ slightly, but the interval is:

(–2975, 175)Now, since the 0 is contained in the Confidence interval, the decision is to not reject the null hypothesis. In other words, the difference in average salaries between the two districts is cero.

I hope it helps!

4 0

3 years ago

1. Consider the following hypotheses:

Andrej [43]

Answer:

See deductions below

Step-by-step explanation:

1)

a) p(y)∧q(y) for some y (Existencial instantiation to H1)

b) q(y) for some y (Simplification of a))

c) q(y) → r(y) for all y (Universal instatiation to H2)

d) r(y) for some y (Modus Ponens using b and c)

e) p(y) for some y (Simplification of a)

f) p(y)∧r(y) for some y (Conjunction of d) and e))

g) ∃x (p(x) ∧ r(x)) (Existencial generalization of f)

2)

a) ¬C(x) → ¬A(x) for all x (Universal instatiation of H1)

b) A(x) for some x (Existencial instatiation of H3)

c) ¬(¬C(x)) for some x (Modus Tollens using a and b)

d) C(x) for some x (Double negation of c)

e) A(x) → ∀y B(y) for all x (Universal instantiation of H2)

f) ∀y B(y) (Modus ponens using b and e)

g) B(y) for all y (Universal instantiation of f)

h) B(x)∧C(x) for some x (Conjunction of g and d, selecting y=x on g)

i) ∃x (B(x) ∧ C(x)) (Existencial generalization of h)

3) We will prove that this formula leads to a contradiction.

a) ∀y (P (x, y) ↔ ¬P (y, y)) for some x (Existencial instatiation of hypothesis)

b) P (x, y) ↔ ¬P (y, y) for some x, and for all y (Universal instantiation of a)

c) P (x, x) ↔ ¬P (x, x) (Take y=x in b)

But c) is a contradiction (for example, using truth tables). Hence the formula is not satisfiable.

7 0

3 years ago

A toxic radioactive substance with the density of 4 mg/cm² is detected in the been detected in the ventilating ducts that was us

Kruka [31]

The formula for half-life is:

$A = P(0.5)^{t/h}$

A is the amount remaining, P is the initial amount, t is the time that has passed, and h is the half-life of the substance. Plug in the values that you know and solve:

$4 = P(0.5)^{35/20} \\ \\ 4 = P(0.5)^{1.75} \\ \\ P = \frac{4}{0.5^{1.75}} \\ \\ P \approx 13.4543426441$

Rounded to the nearest whole number, the density of the substance was about 13<span>mg / cm².</span>

8 0

3 years ago

Part C

makkiz [27]

a = 1, b =14 and y-coordinate is 6 when x = 0.

Solution:

Let us first write the equation of a line.

Take the points are (2, 2) and (6, 10).

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{10-2}{6-2}$

$$m=\frac{8}{4}$

m = 2

Point-slope formula:

$y-y_1=m(x-x_1)$

y - 10 = 2(x - 2)

y - 10 = 2x - 4

Add 10 on both sides,we get

y = 2x + 6

Equation of a line is y = 2x + 6.

To find (a, 8), substitute x = a and y = 8 in the equation,

8 = 2a + 6

Subtract 6 from both sides, we get

2 = 2a

a = 1

To find (4, b), substitute x = 4 and y = b in the equation,

b = 2(4) + 6

b = 8 + 6

b = 14

Substitute x = o in the equation.

y = 2(0) + 6

y = 6

The y-coordinate is 6 when x = 0.

7 0

3 years ago

Can someone help with this please

grigory [225]

Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients. The polynomial is x³- 7x² - 6x + 72.

<h3>What is a polynomial?</h3>

Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients(constants who are in multiplication with those variables) and constants with only operations of addition, subtraction, multiplication and non-negative exponentiation of variables involved.

The polynomial using the given information can be made as shown below.

Given the zeros of the polynomial are -3, 4, and 6.

P(x) = (x+3)(x-4)(x-6) = x³- 7x² - 6x + 72

To check the end behaviour of the function, the graph of the function can be plotted as shown in the below image.

Hence, the polynomial is x³- 7x² - 6x + 72.

Learn more about Polynomials:

brainly.com/question/27343162

#SPJ1

4 0

2 years ago

What is the range of function g? g (x) = x²+6x-5