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Dimas [21]
3 years ago
9

the lacrosse team is raising money by selling cheesecakes. the players plan to sell an entire cheesecake for $24

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
6 0

Answer:

what is the rest of the question

Step-by-step explanation:

then  i can help you answer it.

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PLEASE HELP WITH MATH ASAP!!!!! ITS DUE IN 10 MINS!!! ILL GIVE BRAINLIEST
Irina-Kira [14]

Answer:

1. 37

2. Supplementary

3. Complementary

4. 17

5. 22

Step-by-step explanation:

7 0
2 years ago
Your cousin renews his apartment lease and pays a new monthly rent. His new rent is calculated by applying a discount of $50 to
nasty-shy [4]

Answer:

  • $1100

Step-by-step explanation:

Let the rent be x

<u>Discounted rent </u>

  • x - $50

<u>Increase applied</u>

  • 10%

<u>Final rent:</u>

  • (x - 50) + 10% = (x - 50)*1.1

<u>We know this is equal to x + 5% = 1.05x, comparing now</u>

  • 1.1(x - 50) = 1.05x
  • 1.1x - 1.05x = 55
  • 0.05x = 55
  • x = 55/0.05
  • x = $1100
6 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Janelle practices basketball every afternoon in the driveway each day her goal is to make four more baskets then she made the da
Alla [95]
She made 62 baskets by day 14. 4×13=52+10=62
5 0
3 years ago
Im having such a hard time solving this plz help
expeople1 [14]

Answer: 38 Bags

Step-by-step explanation:

Since there are 19 people and each person needs 24 beads, the total number of beads needed is 19*24=456. Then if this total must be split up into groups of 12 beads, the answer would be 456/12=38.

3 0
3 years ago
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