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BartSMP [9]
3 years ago
14

A construction worker is tasked with tiling two square rooms, room A and room B. Room B has side lengths that are double the sid

e lengths of room A. The construction worker uses one box of tiles to complete the flooring of room A. How many boxes of tiles will they need to complete the flooring of room B?
Mathematics
1 answer:
swat323 years ago
4 0

Answer:

<u><em>4 boxes of tiles.</em></u>

Step-by-step explanation:

Both rooms are square, so each has equal sides.  Let's set a side to room A as x.  It's area would be x^2.  Room B has sides = 2x, so it's area would be (2x)^2 or 4x^2.  The ratio of the areas B/A = 4x^2/x^2.  B/A = 4.

Room B has 4 times the area of A.  If one box of tile completes Room A, Room B would need four times that amount, or 4 boxes.

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Answer:

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Answer:

Presumably you're solving for x here?  Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\

let's solve it.  First we'll multiply both sides by five, making the first term a perfect square:

25x^2 - 10x - 10 = 0\\

Now we'll add 11 to both sides:

25x^2 - 10x + 1 = 11\\

Which makes the left side a perfect square:

(5x - 1)^2 = 11

And now we can solve for x:

(5x - 1)^2 = 11\\\\5x - 1 =  \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86             x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46

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3 years ago
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4 years ago
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For this case we have to, by definition:

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h = 18.4

Answer:

Option C

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3 years ago
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