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Flauer [41]
3 years ago
14

Yo i need someone to talk with im sooo bored

Mathematics
2 answers:
a_sh-v [17]3 years ago
8 0

Answer :

Im free, I guess

Step-by-step explanation:

dolphi86 [110]3 years ago
6 0

Answer:

i'll talk to you

Step-by-step explanation:

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Paula walked on the treadmill for 12 minutes. The machine told her she had a total of 780 strides. What was her rate in strides
Cerrena [4.2K]

Answer:780/12=65

Step-by-step explanation:

7 0
3 years ago
I need help please!
maxonik [38]

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Step-by-step explanation:

rgW

4 0
3 years ago
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A system of two equations has no solution. One equation is -15x+y=18.
DerKrebs [107]

A.

If you multiply the original equation by 3 you get -45x+3y=54, which is the exact same as A, therefore they have infinite solutions.

5 0
3 years ago
Helpppppppppppppppppppppppppppppppppppppppppp
zimovet [89]
Answer:
First choice is the correct one

Explanation:
The given is:
[(x+5) / (x+2)] - [(x+1) / x(x+2)]
First, we will need to have a common denominator and then we will solve the subtraction normally. To get a common denominator, we will have to multiply both numerator and denominator of first term by x.

Therefore:
[(x+5) / (x+2)] - [(x+1) / x(x+2)] = [x(x+5) / x(x+2)] - [(x+1) / x(x+2)]
                                                 = [x(x+5)-(x+1)] / [x(x+2)]
                                                 = (x^2 + 5x - x - 1) / [x(x+2)]
                                                 = [(x^2 + 4x - 1)] / [x(x+2)]

Hope this helps :)

3 0
3 years ago
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = StartFraction neg
Harman [31]

Answer:

x=\frac{-5(+/-)\sqrt{5}} {2}

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

f(x)=x^{2} +5x+5  

equate the function to zero

x^{2} +5x+5=0  

so

a=1\\b=5\\c=5

substitute in the formula

x=\frac{-5(+/-)\sqrt{5^{2}-4(1)(5)}} {2(1)}

x=\frac{-5(+/-)\sqrt{5}} {2}

therefore

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

6 0
3 years ago
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