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3 years ago

(x+14)-(8-2x) equivalent to

1 answer:

7 0

We are given the expression (x + 14) - (8 - 2x). The question is asking us to simplify this expression, and we can do that by first using the distributive property. This gives us x + 14 - 8 + 2x. Now, just combine like terms, which gives us 3x + 6. Therefore, the answer to your query is 3x + 6. Hope this helped and have a phenomenal day!

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FIRST GETS BRAINLEST __ Several tourists are participating in different

coldgirl [10]

Answer:

All you need to do is plot it on a graph. DO it from least to greatest and do it in order

Step-by-step explanation:

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3 years ago

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Find the height of the cylinder. A. 7.2in B. 4.8in C. 2.4in D. 14.4in

vladimir1956 [14]

Answer:

a 7.2

Step-by-step explanation:

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3 years ago

I have litre of bottle of cola i drink 650 ml how much is left

TiliK225 [7]

There are 1000 ml in one liter if you drank 650 ml then:

1000 - 650 = 350

350 ml are left

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3 years ago

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Express the statement "A rectangular field with an area of 120m' has it length 12mn longer than the width" as quadratic equation

navik [9.2K]

Answer:

The quadratic equation is x^2 -12x -120 = 0

where x represents the length of the field

Step-by-step explanation:

We want to make an expression in terms of a quadratic equation;

Let the length of the field be x mm , then the width will be (x-12) mm

Mathematically , the area of the field will be L * B

Thus;

x * (x-12) = 120

That gives;

x^2 -12x = 120

x^2 -12x -120 = 0

6 0

2 years ago

X²+Y²=250 and XY=117<br> What are the values of X and Y?

yan [13]

Answer:

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$

6 0

3 years ago