see the picture attached to better understand the problem
we know that
two tangent segments drawn from the same exterior point are congruent
so
JA=JB ,
LA=LC,
KC=KB
JA=13 units
LA=7 units
kC=10 units
hence
perimeter = JA+JB+LA+LC+KC+KB------> 13+13+7+7+10+10------> =60 units
therefore
the answer is
the perimeter of triangle JKL is 60 units
Answer: n=2
Step-by-step explanation:
Get graph paper make a graph mark them on your graph and since it says (n,-2) its going down because of the negative 2 i don't think this helped but if it did
Answer: the area of the triangle is 23.4 cm²
Step-by-step explanation:
The given triangle is not a right angle triangle. Since two sides and one angle are known, we can either apply the Heron's formula or the Sine formula which is expressed as
Area of triangle = 1/2abSinC
Where a and b are the sides of the triangle and C is the given angle. Therefore,
Area = 1/2 × 8.2 × 6.4 × Sin63
Area = 1/2 × 8.2 × 6.4 × 0.8910
Area = 23.4 cm² to the nearest tenth.
77.2%
To find the probably and at least on you must find the probability of none and subtract from one.
The probability of none can be found like so:
(5+6 over 5+6+7)^3 = .228
1 - .228 = .772
Hope this helps!
