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Luden [163]
3 years ago
10

How many solutions are there? 5(x-3)+2x=x+9

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
4 0

Answer:

4

Step-by-step explanation:

5(x-3)+2x=x+9

5x-15+2x=x+9

5x+2x-x-15=9

7x-x-15=9

6x-15=9

6x=9+15

6x=24

x=24/6

x=4

jok3333 [9.3K]3 years ago
4 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

x  =  4

Step-by-step explanation:

5x+2x-x-15=9

7x-x-15=9

6x=24

x=24/6

Sorry if this didn't help! - Leianna

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The sum of the first 3 terms of a geometric series is 171 and the common ratio is 2/3. What is the first term?​
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Answer:

81

Step-by-step explanation:

let the terms be a,ar,ar²

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a+a(2/3)+a(2/3)²=171

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4 years ago
In a game, you toss a fair coin and a fair six-sided die. If you toss a heads on the coin and roll either a 3 or a 6 on the die,
pochemuha

Using probabilities, it is found that the expected profit of one round of this game is of $0.

A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.

  • One of the two sides of the coin are heads.
  • 2 of the 6 sides of the dice are 3 or 6.

Hence, since the coin and the dice are independent, the <em>probability </em>of winning is:

p = \frac{1}{2} \times \frac{2}{6} = \frac{1}{6}

The expected value is the <u>sum of each outcome multiplied by its respective probability</u>.

In this problem:

  • \frac{1}{6} probability of earning $30.
  • \frac{5}{6} probability of losing $6.

Then:

E(X) = 30\frac{1}{6} - 6\frac{5}{6} = 5 - 5 = 0

The expected profit of one round of this game is of $0.

A similar problem is given at brainly.com/question/24855677

5 0
3 years ago
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