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Serhud [2]
3 years ago
14

Frank has a science test on Monday over the weekend she studies 47 7/8 of an hour for each three hours how many minutes does Fra

nk a study now
Mathematics
1 answer:
9966 [12]3 years ago
6 0
He studied for 8617.5 minutes.
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Solve the proportion.<br><br> 2/13=x/104<br><br> A. 16<br><br> B. 26<br><br> C. 676<br><br> D. 8
Andrej [43]

Answer:

Step-by-step explanation:

its A. 16.

4 0
3 years ago
Read 2 more answers
Solve the given equation. 5^(1/4)/125^(x/3) =1
scZoUnD [109]

Answer:

x = 0.25

Step-by-step explanation:

Rewrite the equation as:

\frac{\sqrt[4]{5}}{125^{x/3}} = 1

\sqrt[4]{5} = 125^{x/3}

(\sqrt[4]{5})^4 = (125^{x/3})^4

5 = 125^{4x/3}

ln5 = ln(125^{4x/3})

ln5 = \frac{4x}{3}ln125

x = \frac{3}{4}\frac{ln5}{ln125} = \frac{3}{4}\frac{1}{3} = \frac{1}{4} = 0.25

3 0
3 years ago
What is 2 3/5 + 1 3/5
Vlada [557]

Answer: 4 1/5


Step-by-step explanation:

Rewriting our equation with parts separated


=2 + 3/5 + 1 + 3/5


Solving the whole number parts


2 + 1= 3


Solving the fraction parts


3/5 + 3/5 = 6/5


Simplifying the fraction part, 6/5,


6/5 = 1 1/5


Combining the whole and fraction parts


3 + 1+ 1/5 = 4 1/5


Solution by Formulas


converting mixed numbers to fractions, our initial equation becomes,


13/5 + 8/5


Applying the fractions formula for addition,


=(13 × 5) + (8 × 5)/5 × 5


=65+40 / 25


=105/25


Simplifying 105/25, the answer is


=4 1/5

6 0
4 years ago
Read 2 more answers
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
4 years ago
If log a^3=x and log a^2=y find log 22^2x+1+2^x=10 what is the value of x
PIT_PIT [208]
If log a^2/82819 then the value of x is 021819201010
4 0
4 years ago
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