The distance travelled is 10 m
The velocity gained at the end of the time is 2 m/s
<h3>Motion</h3>
From the question, we are to determine distance travelled and the velocity gained
From one of the equations of motion for <u>linear motion</u>, we have that
S = ut + 1/2at²
Where S is the distance
u is the initial velocity
t is the time taken
and a is the acceleration
First, we will calculate the acceleration
Using the formula,
F = ma
Where F is the force
m is the mass
and a is the acceleration
∴ a = F/m
Where F is the force
and a is the acceleration
From the given information,
F = 50 N
m = 250 kg
Putting the parameters into the equation,
a = 50/250
a = 0.2 m/s²
Thus,
From the information,
u = 0 m/s (Since the object was initially at rest)
t = 10 s
S = 0(t) + 1/2(0.2)(10)²
S = 10 m
Hence, the distance travelled is 10 m
For the velocity
Using the formula,
v = u + at
Where v is the velocity
v = 0 + 0.2×10
v = 2 m/s
Hence, the velocity gained at the end of the time is 2 m/s
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Answer:
slope = 
Step-by-step explanation:
Calculate the slope m using the slope formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (5, - 3) and (x₂, y₂ ) = (- 9, - 6)
m = 
= 
=
Answer:
a believe it is c..........
Ok so basically solve for y
x-y=12
27+3y=2x
27+3y=2x
subtract 3y from both sides
27=2x-3y
2x-3y=27
x-y=12
multiply by -2
-2x+2y=-24
add them
2x-3y=27
<u>-2x+2y=-24 +</u>
0x-1y=3
-y=3
y=-3
y coordinate is -3
2.
y=2x+14
-4x-y=4
y=2x+14
subtract 2x from both sides
y-2x=14
mulitply both sides by -2
-2y+4x=-28
add the 2 equations
-2y+4x=-28
<u /><u>-y-4x=4 +</u>
-3y+0x=-24
-3y=-24
divide both sides by -3
y=8
y coordinate is 8
1. y coordinate is y=-3
2. y coordinate is y=8<u>
</u>
The domain of the graphed function is [-3, 2)
<h3>How to determine the domain and the range?</h3>
From the given graph, we have the following highlights:
- Minimum x value = -3 (closed circle)
- Maximum x value = 2 (open circle)
Open circles are represented with () while closed circles are represented with []
Hence, the domain of the graphed function is [-3, 2)
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