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3 years ago

A box with a square base has sides of 5" and is 8" tall. What is its volume? Question 1 options: 40 320 200 150

1 answer:

6 0

How you would solve this is 5 x 5 x 8. The base is a square, so that's where the extra 5 is from. So, 5 x 5 x 8 = 200, or C. Hope this helped!

Please give brainliest, I need one more until I get virtuoso

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BlackZzzverrR [31]

Answer:

Step-by-step explanation:

f(x) increases by 2 as x increases by 1 x value.

We know it isn't A since and x value plue 2 would not equal the y value.

But if you multiply each x-value by 2 you get f(x)

8 0

2 years ago

Read 2 more answers

PLZ HELP ME, DUE RN!!

mash [69]

Answer:

Step-by-step explanation:

For us to determine the friends that live exactly halfway between any two other friends, we need to determine the midpoint of any two of the coordinates and check whether the coordinate gotten is any of other people coordinates.

Using the coordinates B (22,5) and Ju (4,5), Using the mid point formula;

m(X,Y) = $(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})\\$

X = $\frac{x_2+x_1}{2}$

X = $\frac{22+4}{2}$

$X = \frac{26}{2}\\ X = 13$

$Y =\frac{y_2+y_1}{2}\\Y = \frac{5+5}{2}\\Y = \frac{10}{2}\\Y = 5$

$(X, Y) = (13, 5)$

Hence the friend that live half way of B (22,5) and Ju (4,5) is J(13, 5)

Similarly as above, using the coordinates of M (11,5) and A (31,5)

X = (11+31)/2

X = 42/2

X = 21

Y = (5+5)/2

Y = 10/2

Y = 5

Midpoint of both friends is (21, 5)

Hence the friend that live half way of M (11,5) and A (31,5) is Ma(21, 5)

Also, using the coordinates of J (13,5) and A (31,5)

X = (13+31)/2

X = 44/2

X = 22

Y = (5+5)/2

Y = 10/2

Y = 5

Midpoint of both friends J and A is (22, 5)

Hence the friend that live half way of J (13,5) and A (31,5) is B(21, 5)

4 0

3 years ago

Help ASAP I really need an answer I don't need links please and if you don't know that answer just don't answer

Salsk061 [2.6K]

Answer:

113

Step-by-step explanation:

note: to find the circumference of a circle using the radius, you use this equation -- 2 $\pi$ r. since the radius is 18, you make the equation 2 $\pi$ 18. that gets you 36 $\pi$ , which, if put into the calculator, is about 113.