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3 years ago

14

A prescription calls for 0.04 grams of medicine for each dose. How many milligrams of the medicine would be contained in 5 doses

?

1 answer:

anyanavicka [17]3 years ago

8 0

Answer:

200

Step-by-step explanation:

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A jewelry store is featuring a diamond in the shape of a square pyramid. The side length of

BARSIC [14]

Answer:

128√5/3 mm³

Step-by-step explanation:

Since we are not told what to find, we can as well look for the volume of the pyramid

Volume of a square pyramid: V = (1/3)a²h

a is the side length of the square

h is the height of the pyramid

Given

a = 8mm

l² = (a/2)² + h²

l² = (a/2)² + h²

6² = (8/2)² + h²

h² = 6² - 4²

h² = 36 - 16

h² = 20

h = √20

Volume of a square pyramid = (1/3)*8²*√20

Volume of a square pyramid = 1/3 * 64 * 2√5

Volume of a square pyramid = 128√5/3 mm³

7 0

3 years ago

fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q

RoseWind [281]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

$\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\$

Let F is a value of the content so, the value is:

$\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\$

Now, we calculate the tooling value:

$\to p[\frac{C}{F}]$

using the baues therom:

$\to p[\frac{C}{F}] = \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }$

$= \frac{ 0.17 \times 0.14 }{0.55 \times 0.15 + 0.28 \times 0.12 + 0.17 \times 0.14 } \\\\= \frac{0.0238}{0.0825 + 0.0336 + 0.0238} \\\\= \frac{0.0238}{0.1399} \\\\=0.1701$

7 0

3 years ago

△HES ≅ △PBN, HE = 3.9 cm, SB = 0.9 cm, and NS = 4.5 cm<br><br> What is the length of ES ?

Natali5045456 [20]

ns +sb = 5.4 cm

sb = en so en can be plugged in for sb

therefor es = 5.4

3 0

3 years ago

Hello please help with my question, I will give brainlyest!

lilavasa [31]

No, John is incorrect.

<h3>Correct work shown:</h3>

$\sf x^2 - 6x - 7 = 0$

$\sf x^2 - 6x = 7$

$\sf x^2 - 6x + 9= 7 + 9$

$\sf (x-3)^2= 16$

$\sf x-3=\pm \sqrt{16}$

$\sf x-3= \pm 4$

$\sf x= + 4 + 3 \quad or \quad x = -4 + 3$

$\sf x= 7 \quad or \quad x = -1$

The correct answer should be x = 7 or x = -1

3 0

2 years ago

Solve 6!<br>pls I need help!!

dolphi86 [110]

Answer:

deep nutz are for you only

8 0

3 years ago