Answer:
For K=0

For K=1:

For K=2:

For K=3:

For K=4:

Step-by-step explanation:
Fifth Root is given by:
![\sqrt[5]{z}=1+0i](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bz%7D%3D1%2B0i)
The above equation will become:

It can be written as:
![z=[cos(0)+isin(0)]^5](https://tex.z-dn.net/?f=z%3D%5Bcos%280%29%2Bisin%280%29%5D%5E5)
|z|=1,
According to De-moivre's Theorem:

Now, Fifth Roots of unity in standard form a + bi :
![\sqrt[5]{z}=[{cos(0+2\pi k)+isin(0+2\pi k)}]^{1/5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bz%7D%3D%5B%7Bcos%280%2B2%5Cpi%20k%29%2Bisin%280%2B2%5Cpi%20k%29%7D%5D%5E%7B1%2F5%7D)
k=0,1,2,3,4
For K=0

For K=1:

For K=2:

For K=3:

For K=4:

The correct answer is x = 2.
Answer:

Step-by-step explanation:
The standard form for a polynomial equation in its factored form is:

Where p and q are the zeros and a is the leading coefficient.
We know that the degree of the polynomial is 5.
We are also given roots at x=3 and x=-2. Hence, our factors are (x-3) and (x+2).
These have a multiplicity of two, so we will square them.
We also know that there is a root at x=4. Hence, the factor is (x-4). This has a multiplicity of 1.
Therefore, our polynomial is now:

We know that the y-intercept is 12. Therefore, if we substitute in 0 for x, we should get 12 for y. Here, we are solving for our a. Therefore:

Evaluate:

Evaluate:

Divide both sides by -144:

Hence, our entire polynomial is:

Answer:
h=3/2
Step-by-step explanation:
Factor and set each factor equal to zero.
h=3/2
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