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Zolol [24]
3 years ago
5

How is he wrong for this math problem if you don’t know it I suggest go to another math problem

Mathematics
2 answers:
konstantin123 [22]3 years ago
6 0

Answer:

Jackson s reasoning is incorrect this because if we multiply with numbers smaller than zero what we get is a smaller number: 54•0.2=27 etc...

Vikki [24]3 years ago
4 0

Answer: There are two cases at least that show that Jackson's reasoning is wrong:  Multiplying decimals and factions less than one by themselves.

Multiplying a Negative number times a positive number will also produce a product that is less than the factors.

Step-by-step explanation:  Fractions times fractions

1/2 × 1/2 = 1/4  A fraction multiplied by itself always yields a smaller product.  1/3×1/3 =1/9

3/8 × 3/4 = 9/32    9/32 is smaller than 3/8 (12/32)  and 3/4 (24/32)

1/12 × 9/10 = 9/120    thats  3/40 . To compare, change to decimals, use a calculator to divide the numerator by the denominator. 1/12 is 0.083333

3/40 is 0.075000

Decimals times decimals  

.5 × .5 = .25   .75 × .75 = .5625

Negative numbers

55 × -5 = -275 .    2 ×-5 = -10

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____ more than 9 is 10
mylen [45]
1 more than 9 is 10. 

That is because 10-9 = 1. 
4 0
3 years ago
Evaluate the line integral by the two following methods. xy dx + x2 dy C is counterclockwise around the rectangle with vertices
Airida [17]

Answer:

25/2

Step-by-step explanation:

Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

\large \displaystyle\int_{C}[P(x,y)dx+Q(x,y)dy]=\displaystyle\int_{a}^{b}[P(x(t),y(t))x'(t)+Q(x(t),y(t))y'(t)]dt

Where P, Q are scalar functions

We want to compute

\large \displaystyle\int_{C}P(x,y)dx+Q(x,y)dy=\displaystyle\int_{C}xydx+x^2dy

Where C is the rectangle with vertices (0, 0), (5, 0), (5, 1), (0, 1) going counterclockwise.

a) Directly

Let us break down C into 4 paths \large C_1,C_2,C_3,C_4 which represents the sides of the rectangle.

\large C_1 is the line segment from (0,0) to (5,0)

\large C_2 is the line segment from (5,0) to (5,1)

\large C_3 is the line segment from (5,1) to (0,1)

\large C_4 is the line segment from (0,1) to (0,0)

Then

\large \displaystyle\int_{C}=\displaystyle\int_{C_1}+\displaystyle\int_{C_2}+\displaystyle\int_{C_3}+\displaystyle\int_{C_4}

Given 2 points P, Q we can always parametrize the line segment from P to Q with

r(t) = tQ + (1-t)P for 0≤ t≤ 1

Let us compute the first integral. We parametrize \large C_1 as

r(t) = t(5,0)+(1-t)(0,0) = (5t, 0) for 0≤ t≤ 1 and

r'(t) = (5,0) so

\large \displaystyle\int_{C_1}xydx+x^2dy=0

 Now the second integral. We parametrize \large C_2 as

r(t) = t(5,1)+(1-t)(5,0) = (5 , t) for 0≤ t≤ 1 and

r'(t) = (0,1) so

\large \displaystyle\int_{C_2}xydx+x^2dy=\displaystyle\int_{0}^{1}25dt=25

The third integral. We parametrize \large C_3 as

r(t) = t(0,1)+(1-t)(5,1) = (5-5t, 1) for 0≤ t≤ 1 and

r'(t) = (-5,0) so

\large \displaystyle\int_{C_3}xydx+x^2dy=\displaystyle\int_{0}^{1}(5-5t)(-5)dt=-25\displaystyle\int_{0}^{1}dt+25\displaystyle\int_{0}^{1}tdt=\\\\=-25+25/2=-25/2

The fourth integral. We parametrize \large C_4 as

r(t) = t(0,0)+(1-t)(0,1) = (0, 1-t) for 0≤ t≤ 1 and

r'(t) = (0,-1) so

\large \displaystyle\int_{C_4}xydx+x^2dy=0

So

\large \displaystyle\int_{C}xydx+x^2dy=25-25/2=25/2

Now, let us compute the value using Green's theorem.

According with this theorem

\large \displaystyle\int_{C}Pdx+Qdy=\displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx

where A is the interior of the rectangle.

so A={(x,y) |  0≤ x≤ 5,  0≤ y≤ 1}

We have

\large \displaystyle\frac{\partial Q}{\partial x}=2x\\\\\displaystyle\frac{\partial P}{\partial y}=x

so

\large \displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx=\displaystyle\int_{0}^{5}\displaystyle\int_{0}^{1}xdydx=\displaystyle\int_{0}^{5}xdx\displaystyle\int_{0}^{1}dy=25/2

3 0
3 years ago
The graph represents the balance of Harrison’s car loan in the months since purchasing the car. A coordinate plane showing Car L
Marina CMI [18]

Answer:

B

Step-by-step explanation:

its the answer

5 0
3 years ago
Is Y=9/3x+2 proportional or no nonprotional
Fiesta28 [93]

Answer:

Non proportional

Step-by-step explanation:

y = mx = proportional

y = mx + b = non proportional

y = mx + b

y = 9/3x + b = non proportional

Hope that helps!

3 0
2 years ago
How does the graph of f(x) = (x + 2)4 + 6 compare to the parent function g(x) = x4?
Alchen [17]

Answer: find the answer in the explanation

Step-by-step explanation:

Given that the transformed graph is of function f(x) = (x + 2)^4 + 6 and the parent function g(x) = x^4

The transformed graph function g(x) was shifted two (2) units to the left and was translated six (6) units upward.

When the function is shifted to the right, the factor of x will be negative and when it's shifted to the left, the factor of x will be positive.

Therefore, function g(x) = x^4 is shifted 2 units to the left and translated 6 units upward to form f(x) = ( x + 2 )^4 + 6.

5 0
3 years ago
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