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kozerog [31]
3 years ago
12

A water desalination plant can produce ×2 x 10^6 gallons of water in one day. How many gallons can it produce in 77 days

Mathematics
1 answer:
wariber [46]3 years ago
8 0

Answer:

nadbagzfs vcs vc vcs da vcs cxag faça fax scccw wccavsvcsvgv vcs ibiah usb ta ta teu Av

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Sveta_85 [38]
Where is the picture I so i can anwser
5 0
3 years ago
1. Kalena was asked to prove ifx(x - 1)(x + 1) = x3 - X represents a polynomial identity. She
Verdich [7]

Answer:

C. Kalena made a mistake in Step 3. The justification should state: -x²

+ x²

Step-by-step explanation:

Given the function x(x - 1)(x + 1) = x3 - X

To justify kelena proof

We will need to show if the two equations are equal.

Starting from the RHS with function x³-x

First we will factor out the common factor which is 'x' to have;

x(x²-1)

Factorising x²-1 using the difference of two square will give;

x(x+1)(x-1)

Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;

a²-b² = (a+b)(a-b) hence;

Factorising x²-1 using the difference of two square will give;

x(x+1)(x-1)

Factorising x(x+1) gives x²+x, therefore

x(x+1)(x-1) = (x²+x)(x-1)

(x²+x)(x-1) = x³-x²+x²-x

The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²

6 0
3 years ago
The rate of change of the function f(x) = 8 sec(x) + 8 cos(x) is given by the expression 8 sec(x) tan(x) − 8 sin(x). Show that t
liq [111]

Answer:

Shown - See explanation

Step-by-step explanation:

Solution:-

- The given form for rate of change is:

                              8 sec(x) tan(x) − 8 sin(x).

- The form we need to show:

                              8 sin(x) tan2(x)

- We will first use reciprocal identities:

                              8\frac{sin(x)}{cos^2(x)} - 8sin(x)

- Now take LCM:

                            8\frac{sin(x)- sin(x)*cos^2(x)}{cos^2(x)}

- Using pythagorean identity , sin^2(x) + cos^2(x) = 1:

                            8*sin(x)*\frac{1- cos^2(x)}{cos^2(x)} = 8*sin(x)*\frac{sin^2(x)}{cos^2(x)}

- Again use pythagorean identity tan(x) = sin(x) / cos(x):

                            8*sin(x)*tan^2(x)

8 0
3 years ago
Read 2 more answers
I am not sure on how to do this ​
sweet [91]

Answer:

CP = 8 cm

Step-by-step explanation:

Given two chords that intersect inside a circle, then then the product of the parts of one chord is equal to the product of the parts of the other chord, that is

DP × CP = AP × PB ← substitute values

6 × CP = 12 × 4

6CP = 48 ( divide both sides by 6 )

CP = 8

8 0
3 years ago
Read 2 more answers
[20points][Precal] Find the cross product of -(3/4)V and (1/2)w if v = <-2, 12, -3> and w = <-7, 4, -6>
Lana71 [14]
\mathbf v=\langle-2,12,-3\rangle=-2\,\vec i+12\,\vec j-3\,\vec k
-\dfrac34\mathbf v=\dfrac32\,\vec i-9\,\vec j+\dfrac94\,\vec k

\mathbf w=\langle-7,4,-6\rangle=-7\,\vec i+4\,\vec j-6\,\vec k
\dfrac12\mathbf w=-\dfrac72\,\vec i+2\,\vec j-3\,\vec k

-\dfrac34\mathbf v\times\dfrac12\mathbf w=\begin{vmatrix}\vec i&\vec j&\vec k\\\frac32&-9&\frac94\\-\frac72&2&-3\end{vmatrix}
=\left((-9)\times(-3)-\dfrac94\times2\right)\,\vec i-\left(\dfrac32\times(-3)-\dfrac94\times\left(-\dfrac72\right)\right)\,\vec j+\left(\dfrac32\times2-(-9)\times\left(-\dfrac72\right)\right)\,\vec k
=\dfrac{45}2\,\vec i-\dfrac{27}8\,\vec j-\dfrac{57}2\,\vec k=\left\langle\dfrac{45}2,-\dfrac{27}8,-\dfrac{57}2\right\rangle
6 0
3 years ago
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