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3 years ago

Which is not a function

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

4 0

Answer:

Step-by-step explanation:

it dose not have a set pattern

Ulleksa [173]3 years ago

3 0

Answer:

Step-by-step explanation:

each input has to have exactly one output

In answer a the input 2 has 5 outputs

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Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco

ANTONII [103]

Answer:

(a) The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(b) The value of P (129 ≤ X ≤ 146) is 0.3462.

(c) The probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

Step-by-step explanation:

The random variable X is defined as the flight time between the two cities.

Since the random variable X denotes time interval, the random variable X is continuous.

(a)

The random variable X is Uniformly distributed with parameters a = 10 minutes and b = 154 minutes.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(b)

Compute the value of P (129 ≤ X ≤ 146) as follows:

Apply continuity correction:

P (129 ≤ X ≤ 146) = P (129 - 0.50 < X < 146 + 0.50)

= P (128.50 < X < 146.50)

$=\int\limits^{146.50}_{128.50} {\frac{1}{154-102}} \, dx$

$=\frac{1}{52}\times \int\limits^{146.50}_{128.50} {1} \, dx$

$=\frac{1}{52}\times (146.50-128.50)$

$=0.3462$

Thus, the value of P (129 ≤ X ≤ 146) is 0.3462.

(c)

It is provided that a randomly selected flight between the two cities will be at least 3 minutes late, i.e. X ≥ 128 + 3 = 131.

Compute the value of P (X ≥ 131) as follows:

Apply continuity correction:

P (X ≥ 131) = P (X > 131 + 0.50)

= P (X > 131.50)

$=\int\limits^{154}_{131.50} {\frac{1}{154-102}} \, dx$

$=\frac{1}{52}\times \int\limits^{154}_{131.50} {1} \, dx$

$=\frac{1}{52}\times (154-131.50)$

$=0.4327$

Thus, the probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

6 0

3 years ago

An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the

sdas [7]

Answer:

$n= 75, 582$

$n= 2300$

$n = 253$

Step-by-step explanation:

Generally the size of the sample sample space is mathematically represented as

$n = \left N } \atop {}} \right. C_r$

Where N is the total number of objects available and r is the number of objects to be selected

So for a, where N = 19 and r = 8

$n = \left 19 } \atop {}} \right. C_8 = \frac{19 !}{(19 - 8 )! 8!}$

$= \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}$

$n= 75, 582$

For b Where N = 25 and r = 3

$n = \left 25 } \atop {}} \right. C_3 = \frac{25 !}{(19 - 3 )! 3!}$

$= \frac{25 *24 *23 *22 ! }{22 ! \ 3!}$

$n= 2300$

For c Where N = 23 and r = 2

$n = \left 23 } \atop {}} \right. C_2 = \frac{23 !}{(23 - 2 )! 2!}$

$= \frac{23 *22 *21! }{21 ! \ 3!}$

$n = 253$

4 0

3 years ago

Ben drinks tea at an incredible rate. He drinks 3 1/2 liters of tea every 2/3 of an hour. Ben drinks tea at a constant rate. How

s344n2d4d5 [400]

Divide 3 1/2 by 2/3. 3 1/2 = 7/2 as an improper fraction, so we have 7/2 ÷ 2/3 = 7/2 * 3/2 = 21/4 = 5 1/4 L

5 0

3 years ago

Read 2 more answers

Graph the solution of y – 2 > 1 on a number line.

Hunter-Best [27]

y-2 > 1
y-2+2 > 1+2
y+0 > 3
y > 3

5 0

3 years ago

Once again co sines . Please help me and include explanation with a clear answer

vladimir1956 [14]

Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)

a = 17, b = 8, c = 16

8^2 = 17^2 + 16^2 - 2*17*16* cos(B)

64 = 289 + 256 - 544 * cos(B)

544*cos(B) = 289 + 256 - 64

544 * cos(B) = 481

cos (B) = 481/544

B = arccos(481/544)

B = 27.8 degrees

8 0

3 years ago