Answer:
An aeroplanes velocity changes from 1250m/s as it comes down to land . It accelerates at 4.9m/s² . Calculate how long it took to come to a stop ?
Step-by-step explanation:
i am sorry in never answeres ur question but pls can u help me i am struggling
Step-by-step explanation: last year
Answer:
10 > v (if you don't trust me, check it yourself. Subsitute v for 10 in the first equation.
Step-by-step explanation:
1) 7 > v - 3
2) add 3 to both sides
3) so 7 plus 3 equals 10
So you basically do this
7 > v - 3 (ad 3 to both sides)
You get 10 > v (which is as simplified as possible)
Hope this helps! :)
Answer:
1st Question
A. 85
2nd Question
B. 71
Step-by-step explanation:
1st Question
{90 + 94 + 96 + 90} = 370/4 = 92.5
{95 + 99} = 194/2 = 97
{87 + 75 + 82 + 85} = 329/4 = 82.25
{71} = 71/1 = 71
.20(92.5) +.25(97) +.30(82.25) +.25(71) = 85.175 Rounded-up = 85
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2nd Question
.10(95) +.20(80) +.50(67) +.20(60) = 71
quadratic formula:
x = <u>-b ± √(b² - 4ac)</u>
2a
7x² - x = 7
subtract 7 from both sides:
7x² - x - 7 = 0
plug values into the quadratic formula:
x = <u>-(-1) ± √((-1)²- 4(7)(-7))</u>
2(7)
simplify:
x = <u>1 ± √(197)</u>
14
