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yan [13]
3 years ago
13

A child grew 314 inches one year and 434 inches the next year. How many inches did the child grow over the two years?

Mathematics
2 answers:
Georgia [21]3 years ago
7 0

Answer:

748

Step-by-step explanation:

434+314=748

Nezavi [6.7K]3 years ago
3 0

Answer:

744 inches

Step-by-step explanation:

314 plus 434

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Am in 8 groups. I am larger than 50. I have 7 in each of my groups. What product am i?
Sergio [31]

Answer:

56

Step-by-step explanation:

8 times 7=56

3 0
2 years ago
Indicate a general rule for the n th term of this sequence. 6a, 3a, 0, -3a, -6a, . . .
GrogVix [38]
Hello : 
(-6a)-(-3a) =(-3a)-(0) = (0)-(3a) = (3a)-(6a) = -3a (arthmetic<span> sequence, the common  -  diff is : d= -3a   the first term is : U1 = 6a
</span><span>a general rule for the n th term is : Un =U1+(n-1)d
Un = 6a +(n-1)(-3a) =
Un = 6a -3an+3a
</span>Un  = -3an +9a

3 0
2 years ago
Does a statistics course improve a student's mathematics skills,as measured by a national test? Suppose a random sample of 13 st
viva [34]

Answer:

There is not enough evidence to support the claim that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

P-value=0.042.

Step-by-step explanation:

The question is incomplete:

The data of the scores for each student is:

Before    After

430        465

485        475

520        535

360        410

440        425

500        505

425        450

470        480

515        520

430        430

450        460

495        500

540        530

We will generate a sample for the difference of scores (before - after) and test that sample.

The sample of the difference is [35 -10 15 50 -15 5 25 10 5 0 10 5 -10]

This sample, of size n=13, has a mean of 9.615 and a standard deviation of 18.423.

The claim is that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

Then, the null and alternative hypothesis are:

H_0: \mu=0\\\\H_a:\mu> 0

The significance level is 0.01.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{18.423}{\sqrt{13}}=5.11

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{9.615-0}{5.11}=\dfrac{9.615}{5.11}=1.882

The degrees of freedom for this sample size are:

df=n-1=13-1=12

This test is a right-tailed test, with 12 degrees of freedom and t=1.882, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>1.882)=0.042

As the P-value (0.042) is bigger than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

4 0
2 years ago
What is the value of x? <br> A:12 <br><br> B:15<br><br> C: 6<br><br> D: 30
const2013 [10]

Answer: C) 6

Step-by-step explanation: the smaller triangle is half of 60. 5x means 5 x 6. Which is 30. 30 is half of 60, so that's your answer

3 0
3 years ago
Read 2 more answers
University theater sold 529 tickets for a play. Tickets cost $25 per adult and $15 per senior citizen. If total receipts were $9
astra-53 [7]

Adults = x

Senior Citizens = y

x + y = 529......1

25x + 15y = 9745...2

Multiply (1) by 15

15x + 15y = 7935....3

25x + 15y = 9745....2

Subtract 3 from 2

10x = 1810

 

x = 181

Substitute x = 181 in

Eq (1)

x + y = 529

181 + y = 529

y = 529 - 181

y = 348

181 adults and 348 Senior Citizens

Hope this helps.

3 0
2 years ago
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