<span>The acceptable weight would be 22.7 grams. Hope this helps :)</span>
Answer:
52
Step-by-step explanation:
(I replaced 
with 
since we are to find 
.)
(By the order of operations, we take care of the exponents before whatever else we have here.)
(By the order of operations, we take care of the multiplication as we see if left to right.)
(By the order of operations, we perform addition/subtraction as we see it left to right.)
(This completes the simplification.)
We could have also put this in our calculator as:
4(4)^2 - 2(4) - 4
This would have returned 52.
The answer is 77
7x11=77
:)
Solution: (a) if 200 adult smokers are randomly selected, how many would we expect to have started smoking before turning 18 years old?
Answer: It is expected that in a random sample of 200 adult smokers, 
will have started smoking before turning 18.
(b) would it be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult smokers? why?
Answer: Yes, it would be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult smokers, because 160 is greater than μ + 2σ
Answer:
1. Proved down
2. proved down
3. f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5
Step-by-step explanation:
Let us explain how to solve the question
∵ f(0) = -20, f(n) = f(n - 1) - 5 for n > 1
→ That means we have an arithmetic sequence with constant
difference -5 and first term -20
1. → f(1) means we need to find the second term, which equal the
term - 5
∵ f(1) means n = 1
∴ f(1) = f(1 - 1) - 5
∴ f(1) = f(0) - 5
∵ f(0) = -20
∴ f(1) = -20 - 5 → Proved
2. → f(3) means we need to find the third term, which equal the
second term - 5
∵ f(3) means n = 3
∴ f(3) = f(3 - 1) - 5
∴ f(3) = f(2) - 5
→ f(2) = f(1) - 5
∵ f(1) = -20 - 5
∴ f(2) = [-20 - 5] - 5 = -20 - 5 - 5
∴ f(3) = [-20 - 5 - 5] - 5
∴ f(3) = -20 - 5 - 5 - 5 → Proved
3. → From 1 and 2 we notice that the number of -5 is equal to n,
at n = 1 there is one (-5), when n= 3 there are three (-5)
∵ n = 10
∴ There are ten (-5)
∴ f(10) = -20 - 5(10)
∴ f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 → Proved
