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AURORKA [14]
3 years ago
5

Write the product in standard form (2x + 5) ^2

Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

4x^2+20x+25

Step-by-step explanation:

(2x+5)^2 = (2x+5) (2x+5)

Using the foil method : 2x(2x) = 4x^2

(2x) (5) = 10x

(2x) (5) = 10x

5 (5) = 25

Combine like terms

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40y^14/10y^8 simplify radicals and use properties of rational exponents
Vadim26 [7]

Answer:

4y^6

Step-by-step explanation:

Take out the constants:

40y^14/10y^8

= 40/10 * y^14 / y^8

= 4 * y^(14-8)

= 4 * y^6

= 4y^6

Hope this helped you :3

7 0
4 years ago
Which expression is equivalent??? help!
dexar [7]

Answer:

The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

Step-by-step explanation:

Given:

\sqrt[3]{256x^{10}y^{7} }

Solution:

We will see first what is Cube rooting.

\sqrt[3]{x^{3}} = x

Law of Indices

(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}

Now, applying above property we get

\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y   )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})

∴ The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

5 0
3 years ago
What are to numbers that multiply to make 18 but add up to negative 9​
balandron [24]

Answer:

I think 3 and 6

Step-by-step explanation:

8 0
3 years ago
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Solve the following problems:
neonofarm [45]

Answer:

Step-by-step explanation:

tey to analyze the problems

4 0
2 years ago
Hurry pls Its timed
suter [353]

Answer:

y = 9

Step-by-step explanation:

We notice that both points have a y-coordinate of 9. Since they are the same, the equation must be y = 9 because the function can't "dip" or "rise", otherwise it would be a piecewise function and not a linear function. The equation y = 9 basically means that no matter what x is, y will always be 9.

7 0
3 years ago
Read 2 more answers
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