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AURORKA [14]
3 years ago
5

Write the product in standard form (2x + 5) ^2

Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

4x^2+20x+25

Step-by-step explanation:

(2x+5)^2 = (2x+5) (2x+5)

Using the foil method : 2x(2x) = 4x^2

(2x) (5) = 10x

(2x) (5) = 10x

5 (5) = 25

Combine like terms

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Kevin Horn is the national sales manager for National Textbooks Inc. He has a sales staff of 40 who visit college professors all
Oduvanchick [21]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Given values:

38, 40, 41, 45, 48, 48, 50, 50, 51, 51, 52, 52, 53, \\\\54, 55, 55, 55, 56, 56, 57, 59, 59, 59, 62, 62, 62, \\ 63, 64, 65,66, 66, 67, 67, 69, 69, 71, 77, 78, 79, 79

Total staff=40

In point a:

To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.

The midterms =55 and 59 so,

Median = \frac{55+59}{2} = \frac{114}{2}=57

In point b:

First-quarter Q_1 = \frac{1}{4} \text{number of 8th call}

                           =\frac{1}{4} \times  30 th \\\\= 7.5 th

The first quarterlies are 7.5th \  \ that  \ is = (7+0.5)th\ \  term

therefore the multiply of 0.5  by calculating the difference of the 7th and 8th term are:

=0.5 \times 0= 0 \\\\\to Q_1 = 50+0=50 \\\\\to Q_3=\frac{3}{4} \text{number of 8th call} \\\\=\frac{3}{4} \times  30 th \\\\=22.5 \ th  = (22+0.5)th  \ \ term

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

= 0.5 \times 1=0.5 \\\\\to Q_3= 63+0.5=63.5

In point c:

First decile D_1 = \frac{1}{18} \text{number of 8th call}

= \frac{1}{10} \times  30 th \\\\= 3rd \ \ term\\\\\to D_1= 41 \\\\\to D_9= \frac{9}{10} \times  8\  th\  call\\\\=\frac{9}{10} \times  30 th \\\\=27th \ \ term\\\\\to D9 = 67

In point d:

quartiles are:

Q_1= 51.25 \\\\Q_3=66

The right answers for the decile are:

D_1=45.3 \\\\ D_9=76.4

As for D) P_{33} = 53.53will be available.

7 0
2 years ago
WILL GIVE BRAINLIEST! Find k so that (5, k) is equidistant from (–1, 2) and (3, 0).
pochemuha

Answer:

9

Step-by-step explanation:

So first I created 2 distance forumlas and set them equal to each other

\sqrt{(5+1)^2+(k-2)^2} =\sqrt{(5-3)^2+(k)^2}

then I simplified them

(5+1)^2+(k-2)^2 =(5-3)^2+(k)^2\\

36 + k^2 - 4k +4 = k^2 + 4

-4k + 36 = 0\\

4k = 36

k = 9

when k = 9, the two distances are equal

7 0
3 years ago
Who can get this correct? Marking most Brainly
Helen [10]

Answer:

I think it's A

Step-by-step explanation:

4 0
3 years ago
Find the unknown factor.<br> 0= blank x (8 x 3)
algol [13]
I think the answer is 0

8*3=24

24 *0=0
3 0
2 years ago
Read 2 more answers
In the number 3,335 how many times greater is the value of the 3 on the left than the 3 on the right
AlekseyPX

Answer:

(If they were talking about 3,335, then) 100 times greater

(If they were talking about 3,335 then) 10 times greater

Step-by-step explanation:

When you visualize it, ignore the other numbers and think of only the threes.

Count how many spaces/places they are from each other, and that's how many 0s you should put after a 1 as your answer.

Same as decimal moving and multiplying by 10's.

8 0
3 years ago
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