The distance between the points A to B is 899.9 feet. After rounding off the nearest integer we get 900 feet as the final answer.
Given we know that CD is perpendicular to AD.
The distance between CD is 139 feet.
As from points A the boat's crew measure the angle of elevation to the beacon as 6°
therefore, m∠A = 6°
Another time the angle of elevation is measured from point B which is 19°.
therefore, m∠DBC = 19°
tan 19° = CD/BD
BD = CD/tan19°
BD = 136/tan 19°
now for tan 6° = CD/AD (tangent is opposite over adjacent)
AD = CD/tan 6°
AD = 136/tan 6°
AB = AD ₋ BD
AB = 136/tan 6° ₋ 136/tan 19°
AB = 1295.2 ₋ 395.3
AB = 900 feet
hence the distance from point A to B is 900 feet.
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Answer:
3.14
Step-by-step explanation:
it will go on foreever
Plug in 4 for x and solve equation like so. c=2
Let Y = total cost of both schools.
The total cost would be ( number of credits at Westside x 98) + (number of credits at Pinewood x 115).
The total number of credits he is taking is 14.
If w is the number of credits at Westside, then for Westside you have 98w ( $98 times the number of credit hours)
The equation is now y = 98w + (number of credits at Pinewood x 115).
The number of credit hours at Pinewood would be the total credit hours 14 minus the credit hours at Westside w, so you have 14-w, which needs to be multiplied by the cost at Pinewood.
The equation is now y = 98w + 115(14-w)
This can be simplified using the distributive property to:
Y = 98w + 1610 - 115w
Y = -17w + 1610
