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Archy [21]
3 years ago
7

DetermIne the inverse function of f(x) = 1/3 + 6 Please show work

Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:

f(x)⁻¹ = 3x - 18

Step-by-step explanation:

I'm going to assume that 1/3 is the coefficient of the x.

f(x) = 1/3x + 6

y = 1/3x + 6

x = 1/3y + 6

x - 6 = 1/3y

3x - 18 = y

f(x)⁻¹ = 3x - 18

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iren2701 [21]

Answer:

2x^3\sqrt[3]{4}

Step-by-step explanation:

We have been given an expression \sqrt[3]{4x^2} *\sqrt[3]{8x^7} and we are asked to find the product of our given expression.

Using exponent rule of power to powers (a^{mn}=(a^m)^n) we can write 8x^7 as (2x^2)^3x and 4x^2=(2x)^2.

Upon substituting these values in our expression we will get,

\sqrt[3]{4x^2} *\sqrt[3]{(2x^2)^3x}

Using exponent rule \sqrt[n]{x^m} =x^{\frac{m}{n}} we will get,

\sqrt[3]{4x^2} *2x^2\sqrt[3]{x}

Multiplying \sqrt[3]{x} by \sqrt[3]{4x^2} we will get,

\sqrt[3]{4x^3} *2x^2

Using exponent rule \sqrt[n]{x^m} =x^{\frac{m}{n}} we will get,

x\sqrt[3]{4}*2x^2

x*2x^2\sqrt[3]{4}

2x^3\sqrt[3]{4}

Therefore, the simplest form of the product of our given expression will be 2x^3\sqrt[3]{4}.

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