Question

If a concrete mix contains 1-1/2 cubic feet of gravel, 1/2 cubic foot of water,

Answer 1

Answer:

The correct answer is "50%".

Step-by-step explanation:

The given values are:

Gravel,

= $(1-\frac{1}{2} )$

Water,

= $\frac{1}{2}$

Cement,

= 1

Sand,

= 2

Now,

The total mixture will be:

= $Gravel+Water+Cement+Sand$

By substituting the values, we get

= $(1-\frac{1}{2} )+\frac{1}{2} +1+2$

= $\frac{1}{2} +\frac{1}{2} +1+2$

= $4 \ cubic \ feet$

hence,

The percentage of sand will be:

= $\frac{Sand}{Total}\times 100$

= $\frac{2}{4}\times 100$

= $50$%