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il63 [147K]
3 years ago
15

Find Arc measure of ABC

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
8 0
268


Hopefully that helps
Softa [21]3 years ago
4 0

Answer:

268°

Step-by-step explanation:

In\: \odot O, AB is diameter.

So, \widehat{AB} \:\&\: \widehat {BA} are semicircular arcs.

\therefore m\widehat {AB} =m\widehat {BA} = 180\degree

\because \: m\widehat {BC} = m\widehat {BA} - m\widehat {CA}

\therefore \: m\widehat {BC} = (180-92)\degree

\therefore \: m\widehat {BC} =88\degree

\because m\widehat {ABC} = m\widehat {AB}+m\widehat {BC}

\therefore m\widehat {ABC} = 180\degree+88\degree

\therefore m\widehat {ABC} = 268\degree

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No spams<br>easy one , thx for answering ~​
SSSSS [86.1K]

Answer:

Step-by-step explanation:

l// m , t is transversal.

Corresponding angles are equal.

3x - 20 = 2x + 10

Add 20  to both sides

3x  = 2x + 10 + 20

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Subtract 2x from both sides

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3 years ago
Express the number 0.00001038 in scientific notation
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For this case it is observed that the "zeros" are to the left of the expression, therefore the exponent, to be expressed in scientific notation, will be negative. That is to say:

10.38 * 10^ {- 6}

This means that by running the decimal 6 spaces to the left we will get the initial expression.

ANswer:

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4 years ago
An outside thermometer reads -4 degrees at 7:00 a.m. By 2:30 p.m. the temperature outside has increased by 11 degrees. At 2:30 p
Gnesinka [82]

Answer:

-169 degrees

Step-by-step explanation:

It doesn't make much sense... but let's answer the question anyway.

First task is to determine what's the temperature outside at 2:30 PM.

We know that it's 11 degrees cooler than it was at 7 AM, so -4 - 11 = -15 degrees.

Abram's house is 4 degrees less than 11 times the outside temperature, so we can express that as:

House = 11 x - 4    - where x is the temperature outside.

If we replace the numbers we get: 11 * (-15) - 4 = -165 - 4 = -169 degrees

Abram's house is an extremely cold freezer!

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