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posledela
3 years ago
5

A tech company bought a number of computers for its employees: 66 costing \$1600$1600 each, 44 costing \$1200$1200 each, and yy

costing \$900$900 each, where yy is a positive odd integer. If the median price for all the computers purchased by the company was \$1200,$1200, what is the greatest possible value of yy
Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

5

Step-by-step explanation:

A tech company bought a number of computers for its employees: 6 costing $1600 each, 4 costing $1200 each, and y costing $900 each, where y is a positive odd integer. what is the greatest possible value of y

Solution:

The median of a group of numbers is the middle number when the group of numbers have been arranged either in ascending of descending other. The median of an even group of numbers is the average of the two most middle most numbers while the median of an odd group of numbers is the middle number.

Since there are 6 computers costing $1600, 4 computers costing $1200 each and y computers costing $900 each. Since y is odd, hence y + 6 + 4 would be odd and the median would be the middle number.

Given that the median price = $1200, this means that the middle of the group of numbers is $1200

900, 900, ..., 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

Since y is odd, for the median price to be $1200, y has to be 3 or 5.

If y = 3:

900, 900, 900, 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

median = $1200

If y = 5:

900, 900, 900, 900, 900, 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

Median = $1200

Therefore the greatest possible value of y is 5

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Lubov Fominskaja [6]

Answer:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

Step-by-step explanation:

For this case we have the following distribution given:

X        0         1       2       3       4         5        6

P(X)  0.3   0.25   0.2   0.12   0.07   0.04   0.02

For this case we need to find first the expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And replacing we got:

E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61

Now we can find the second moment given by:

E(X^2) =\sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97

And the variance would be given by:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

 

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ch4aika [34]

Answer:

13 miles

Step-by-step explanation:

3 1/4 can be changed to 3.25

Then multiply 3.25 (the time) and 4 (the distance per hour) to get 13.

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horsena [70]
The GCF of the three terms (9a, -18b and 21c) is 3

Rewrite each of the terms so 3 is a factor
9a = 3*3a
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21c = 3*7c

So we can say...
9a - 18b + 21c = 3*3a - 3*6b + 3*7c
9a - 18b + 21c = 3(3a - 6b + 7c)

Answer: 3(3a - 6b + 7c)

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VARVARA [1.3K]

Answer:

x=5

Step-by-step explanation:

Alright you will need to use PEMDAS for this

  • Parenthesis
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Step 1

9(3x – 16) + 15 = 6x – 24 You will remove parenthesis here

27x-129=6x-24

Step 2

Then subtract 6x,

27x-129=6x-24

21x-129=-24

Step 3

Then you add 129 to the sides,

21x-129=-24

21x=105

After that, you divide the sides by 21  so that you can get your answer

5

So therefore, your answer will be x=5

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Vaselesa [24]

Answer:

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