Answer:
The correct option is B. The area of the figure is 40.4 units².
Step-by-step explanation:
The line AB divides the figure in two parts one is a rectangle and another is semicircle.
The distance formula is
The length of AB is
The length of AD is
Since AB=AD, therefore ABCD is a square. The area of the of square is
The area of square is 29 units².
The area of a semicircle is
Since AB is the diameter of the semicircle, therefore the radius of the semicircle is
The area of the semicircle is
The area of the figure is
Therefore the area of the figure is 40.4 units². Option B is correct.
Answer:
-12.90, -12.55, 10.25, 10.75, 12.50
Step-by-step explanation:
this is from least to greatest
We want to see if the given function represents a linear function.
We will see that yes, it does.
So we have the function:
y = f(x) = 30 + 5*x
And a general linear function is written as:
y = a*x + b
where a is the slope and b is the y-intercept.
Comparing these two, we can see that both have the same general shape, thus, our function is also a linear function.
A graph of our function also can be seen below, where it is evident that it is a line.
If you want to learn more, you can read:
brainly.com/question/20286983
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
