Yes
factor out the 2z^2 in each term
(2z^2)(z^2-5z+4)
factor some more
z^2-5z+4
find what 2 numbers multiply to get 4 and add to get -5
the numbers are -1 and -4
(z-1)(z-4)
the factored form is
(2z^2)(z-1)(z-4)
Y = ln |1 + t - t^3| = (1 - 3t^2)/(1 + t - t^3)
Answer:
61
Step-by-step explanation:
Use PEMDAS (Parenthesis first, Exponents second, Division/Multiplication third, Addition/Subtraction last)
(9+2) x 6 - 5
11 x 6 - 5
66 - 5
61
Answer:
5x+10
Step-by-step explanation:
3x+2x=5x
5x +10
