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Rufina [12.5K]
3 years ago
13

A rectangle has a length of 5^3 units and a width of 5^2 units. What is the area of the​ rectangle? Write your answer as a power

of 5. Cubic Units , Units, or square Units?
Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

points sorry

Step-by-step explanation:

i need points for my questions sorry

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An instructional video is 4.2 minutes long. How long is the video in seconds? How long is it in hours?
valkas [14]
First we convert it in seconds.

Number of seconds in 1 minute = 60 seconds
Therefore,
Number of seconds in 4.2 minutes = 4.2 x 60 = 252 seconds.

Next we convert it in hours.

60 minutes make up an hour. So we can write,
Number of hours in 60 minutes = 1 hour
Number of hours in 1 minute = 1/60 hour
Number of hours in 4.2 minutes = 1/60 x 4.2 = 0.07 hour


Therefore, the video is 252 seconds or 0.07 hour long. 
5 0
3 years ago
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Calculate the area of the following composite figure.
Alexeev081 [22]
\bold{ANSWER:}
100 units^2

\bold{EXPLANATIONS:}

4 0
2 years ago
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Help on geometry plzzzz find b
Nikitich [7]

Answer:

5.5 cm

Step-by-step explanation:

3 0
3 years ago
Which is twenty thousand eight hundred twelve written with base-ten numerals
vagabundo [1.1K]

Answer:

The answer is 20812

The numeral system we use is a base ten numeral system. Base ten numeral numbers are: 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

The number has:

2 "tens thousands" = 2 * 10000 = 20000

0 "thousands" = 0

8 "hundreds " = 8 * 100 = 800

1 "tens" = 1 * 10 = 10

2 "ones" = 2 * 1 = 2

Sum all the results => 20000+800+10+2 = 20812

That is how you write a number using base ten numerals (numbers from 0 to 9)

6 0
3 years ago
Solve pls, ans should be 0, add working
Bond [772]

Step-by-step explanation:

<u>Given</u>: {x+(1/x)}³ = 3

<u>Asked</u>: x³ + (1/x³) = ?

<u>Solution:</u>

<u>Method</u><u> </u><u>1:</u>

We have, {x+(1/x)}³ = 3

Comparing the expression with (a+b)³, we get

a = x

b = (1/x)

Using identity (a+b)³ = a³+b³+3ab(a+b), we get

⇛{x+(1/x)}³ = 3

⇛(x)³ + (1/x)³ + 3(x)(1/x){x + (1/x)} = 3

⇛(x*x*x) + (1*1*1/3*3*3) + 3(x)(1/x){x + (1/x)} = 3

⇛x³ + (1/x³) + 3(x)(1/x){x + (1/x)} = 3

⇛x³ + (1/x³) + 3{x + (1/x)} = 3

⇛x³ + (1/x³) + 3(x) + 3(1/x) = 3

⇛x³ + (1/x³) + 3x + (3/x) = 3

Our answer came incorrect.

Let's try..

<u>Method</u><u> </u><u>2</u><u>:</u>

We have,

[x+(1/x)]³ = 3

On taking cube root both sides then

⇛³√[{ x+(1/x)}³ ] = ³√3

⇛x+(1/x) = ³√3 -----(1)

We know that

a³+b³ = (a+b)³-3ab(a+b)

⇛x³+(1/x)³ = [x+(1/x)]³ - 3(x)(1/x)[x+(1/x)]

⇛x³+(1/x³) = (3)-3(1)(³√3)

[since, {x + (1/x)} = ³√3 from equation (1)]

⇛x³+(1/x)³ = 3-3 ׳√3

⇛x³ + (1/x³) = 3- ³√81 (or )

⇛x³ + (1/x³) = 3(1-³√3)

Therefore, x³ + (1/x³) = 3(1 - cube root of 3)

It is impossible to get zero

6 0
3 years ago
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