2X^2+4X-8-X^2+6X-4
X^2+4X-8+6X-4
X^2+10X-12
Answer:
34
Step-by-step explanation:
Answer:
1a
2b
3a
4c
5c
6c
7a
8d
9b
10b
11a
12c
13b
14a
15a
Step-by-step explanation:
So hmm notice the picture below
you have the center, and a point on the circle... all you need is the radius

then use that radius in the circle's equation
The one under the one you picked but im not 100% sure