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trasher [3.6K]
3 years ago
15

4 divided by 2/3 simplest form

Mathematics
2 answers:
Verdich [7]3 years ago
6 0

Answer:

6

See photo for explaination.

OLga [1]3 years ago
5 0

Answer:

6

Step-by-step explanation:

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Given that r=(9,8,3),v=(6,7,-1)and w=(-3,3,7), evaluate (r+v) w
lakkis [162]

Answer:

(-45,45,14)

Step-by-step explanation:

(r+v)*w=((9,8,3)+(6,7,-1))*(-3,3,7)=(15,15,2)*(-3,3,7)=(-45,45,14)

Does this help (I'm not sure of the rightness of this answer), if it did, please mark brainliest

4 0
3 years ago
What is the slope-intercept form of the equation -3x + y=12
Musya8 [376]
Answer: y=3x+12

explanation: just add the 3x to the 12
8 0
3 years ago
Read 2 more answers
How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
Help please, my teacher is horrible at explaning
Inessa05 [86]

10 hours and 10 minutes

6 0
4 years ago
Read 2 more answers
18 PTS! From the equation below, identify the slope and a point on the line. y−3=−2(x+1)
omeli [17]

<u>ANSWER:  </u>

The slope of the given equation is -2 and a point on the given line is (-1, 3)

<u>SOLUTION:</u>

Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)

We need to find the slope of the given equation and a point through which the given line passes.

Given equation is in the form of point slope form  .i.e \mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right) --- eqn 2

where,"m" is the slope of the line

\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) is point on that line.

Now, by comparing (1) and (2)

m = -2

x_{1}=-1

y_{1}=3

so, the slope of the given equation is -2  and a point on the given line is (-1, 3)

7 0
3 years ago
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