1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inessss [21]
3 years ago
12

Help me please I really need it

Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0

y = - 2x + 7; slope m = -2

Parallel lines, slope is the same

So y = -2x + b

b = y + 2x

Passing thru (4 , 1)

Plug in

b = 1 + 2(4)

b = 9

Equation

y = - 2x + 9

You might be interested in
Help please!!!!!!!!!!!!!!!!!!!
irakobra [83]

Answer:

1. The elephant should be given _ fl oz.

2. Every term in Pattern B is 1/4 the corresponding term in Pattern A.

3. 0.9 < 1.1

4. There are 7 tons in 14,000 pounds.

5. There are 17900 Milligrams in 17.9 grams.

Step-by-step explanation:

1. One ton is 2,000 pounds. So you would have to multiply 5.5 x 2,000.

5.5 x 2,000 = 11,000

Then you have to divide 11,000 by 250.

11,000/250 = 44

2. Every term in Pattern B is 4 times less than the term in Pattern A.

3. 0.9 is smaller than 1.1.

4. One ton is 2,000 pounds. 14,000/2,000 is 7 so this would mean that 14,000 pounds is 7 tons.

5. One gram is 1,000 milligrams, so you would have to multiply 17.9 by 1,000. This gives you 17900.

4 0
2 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
Are they right??? <br><br> Due tomorrow
DedPeter [7]
Yes they are right you did a great job!
8 0
3 years ago
A number is chosen at random from 1 to 25 find the probability of selecting a number less than 4​
stira [4]

3/25 I hope I helped

7 0
3 years ago
Read 2 more answers
How many days would it take Martin to swim swim 60000 meters
PolarNik [594]

Answer:

300

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • Answer 7x9-8+11-6[5+2(-3)]
    14·2 answers
  • Write this polynomial in descending order. <br> -7+8x^2-4x
    12·1 answer
  • There are 4 cookies if there is 1/4 of a cookie in each bag how many bags will there be
    10·1 answer
  • What is 1/4 as a decimal
    10·2 answers
  • There are 7 ducks swimming in a pond. If 3 have green wings and 4 have blue wings, what fraction of the ducks have green wings?
    15·2 answers
  • Convert to Standard Form <br> 13-6x-y=0
    8·1 answer
  • How do you do this answer this pls
    6·2 answers
  • How many judges should be selected to estimate the population mean wage with 90% confidence and a margin of error of $2.00
    5·1 answer
  • Evaluate x1 - x1 + x0 for x = 2.<br> 0<br> 1/2<br> 1 1/2<br> 2 1/2
    5·1 answer
  • Help with Questions 4 and 5!<br> Will mark Brainliest for the best and accurate answers!
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!