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mojhsa [17]
3 years ago
12

The cost a dog walker for n hours is given by f(n) = 5 + 10n. Which statement is true?

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

C. For each additional hour of service, the price of the dog walker increases by $10.

Step-by-step explanation:

Hope this helps!

:)

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The answer is A (y = 2x - 2)

Step-by-step explanation:

B and D aren't correct because the y-intercept is a positive 2 instead of negative 2 like the graph shown. We're now left with A and C. Go on one point of the graph and count up or down to go on the same y value as the other point. Go left or right and count until you go to the same point. Remember that the slope equation is rise/run. Rise meaning up or down. Run meaning left or right.

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Jamie and Sara went shopping at the mall. Jamie spent $25 more than three times what Sara spent. Jamie spent $154.
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1. Star Inc. has Year 1 revenues of $80 million, net income of $9 million, assets of $65 million, and equity of $40 million, as
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3 years ago
Please answer asap.will mark you as brainliest
shtirl [24]

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= and \leq and \geq

Step-by-step explanation:

Absolute value -9 is 9, but there is a negative sign so it is -9

-9=-9

Greater than or equal to works because of the equal sign.

Less than or equal to also works because of the equal sign.

8 0
3 years ago
On a town map, each unit of the coordinate plane represents 1 mile. Three branches of a bank are located at A(−3, 1), B(3, 3), a
Andrei [34K]

Answer:

The minimum total distance the employee may have driven before getting stuck in traffic is 8.3 miles

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of the distance between to points (x_{1},y_{1})

  and (x_{2},y_{2}) i s d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

- So at first we will find the distance between the three points

∵ A = (-3 , 1) , B = (3 , 3) , C = (3 , -1)

- By using the rule of distance

∴ AB=\sqrt{(3--3)^{2}+(3-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325

∴ BC=\sqrt{(3-3)^{2}+(-1-3)^{2}}=\sqrt{0+16}=4

∴ AC=\sqrt{(3--3)^{2}+(-1-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325

∵ Each unit coordinate plane represents 1 mile

∵ AB = 6.3 units

∴ The distance between branches A and B = 6.325 miles

∵ BC = 4 units

∴ The distance between branches B and C = 4 miles

∵ AC = 6.3 units

∴ The distance between branches A and C = 6.325 miles

- A bank employee drives from Branch A to Branch B and then

 drives halfway to Branch C before getting stuck in traffic

∵ The distance from branch A to branch B is 6.325 miles

∵ The distance from branch B to branch C is 4 miles

∵ The half way from branch B to branch C = 1/2 × 4 = 2 miles

∴ The distance the employee may have driven before getting

   stuck in traffic = 6.325 + 2 = 8.325 miles

∴ The minimum total distance the employee may have driven

   before getting stuck in traffic is 8.3 miles

8 0
3 years ago
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