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ivann1987 [24]
3 years ago
11

If line P bisects segmentAD at point O and if AO=z+4 and AD =3z-11, find OD

Mathematics
1 answer:
sleet_krkn [62]3 years ago
3 0

Answer:

Line P bisects AD at O.

AD = AO + OD

(3z - 11) = (z + 4) + OD

(3z - 11) - (z + 4) = OD

3z - 11 - z - 4 = OD

2z -15 = OD

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Th picture below represent the image you are referring.

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6 0
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Read 2 more answers
Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K
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<h2>Hello!</h2>

The answer is:

Ava and Kelly will be 3/4 mile apart after 0.375 hours.

<h2>Why?</h2>

To calculate when will Ava and Kelly be 3/4 mile apart, we need to write the equations for both Ava's and Kelly's positions.

Writing the equations we have:

For Ava:

x_A=x_o+v_ot\\\\x_A=0+v_o*t\\\\x_A=v_{o(ava)*t

For Kelly:

We need to calculate when Kelly will be 3/4 mile apart becase is running faster than Ava, so, writing the equation we have:

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Now, substituting the equation for Ava into the equation for Kelly, we have:

x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+\frac{3}{4}mile}=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+0.75mile}=x_{o}+v_{o(Kelly)}*t\\\\6mph*t+0.75mile=8mph*t\\\\0.75mile=2mph*t\\\\t=\frac{0.75miles}{2mph}=0.375hours

To prove  that the result is correct, we just need to substitute the obtained value for time into both equations, so, substutiting we have:

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x_A=v_{o(ava)*t=6mph*0.375hours=2.25miles

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x_K=v_{o(Kelly)}*t=8mph*0.375=3miles

There is a difference of 0.75 miles or 3/4 mile between Ava and Kelly, so, the obtained value for time is correct.

Therefore, we have that Ava and Kelly will be 3/4 mile apart after 0.375 hours.

Have a nice day!

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Answer:

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